Question

我在完成大学时的练习时遇到了一些麻烦。基本上他们要求我获得一些用户输入，然后计算总和，平均，最小和最大输入以及范围。

一切正常，直到我尝试获得最小值。我已经仔细观察并亲自尝试过，但由于某些原因我无法让它工作。这是我的代码：

   import java.util.Scanner;

   public class IntSequence {
    public static void main ( String arg[]){

    Scanner input = new Scanner(System.in);
    int sum = 0;
    double avg = 0;
    int choice = 0;
    int i = 1;
    int smallestInput = Integer.MAX_VALUE;
    int largestInput = Integer.MIN_VALUE;
    int range = 0;


    System.out.println("Please enter an integer: ");
    for(; i <= 1000; i++){
        choice = input.nextInt();
        if (choice <= 0)
            break;
        sum = sum + choice;
        avg = sum / i;
        if(choice > largestInput){
            largestInput = choice;
        }
        if(smallestInput < choice){
            smallestInput = choice;
        }



    }
    System.out.println("The sum of all integers is " + sum);
    System.out.println("The average of the input integers is " + avg);
    System.out.println("The largest input is: " + largestInput);
    System.out.println("The smallest input is: " + smallestInput);




  }
}

Answer 1

尝试将更改选择小于minimalInput 像这样：

if(choice < smallestInput){
        smallestInput = choice;
    }

不是这样：

if(smallestInput < choice){
        smallestInput = choice;
    }

请注意0仍被用户输入：

if (choice < 0) break;

如何获取要打印的用户输入的MIN值

1 个答案: