Question

我有一个执行以下操作的脚本

减去dict键中的值
将数组转换为已排序的列表
从第二个
然后第二个来自第三个
等等。

问题是源数据中的某些值为null，这会抛出TypeError。我试图抛出一个条件，但它仍然试图减去Nones。

以下是包含一些示例数据的代码：

eLinks = {'726122193.0': [1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340, 1310, 1315, 1320, 1325, 1330, 1335, 1340], '23607015.0': [None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None, None, None, None, 90, 95, 130, 2070, None, None, None, 580, 585, 610, 615, 2355, 2360, 1945, 1950, 125, 130, None, None, None]}

eOut = {}
for key, lis in eLinks.iteritems():
    eCheck = []
    sLis = sorted(lis)
    for i, _ in enumerate(sLis[:-1]):
        if i is not None:
            dif = sLis[i+1] - sLis[i]
            if dif > 20:
                eCheck.append(dif)
            eOut[key] = eCheck

Answer 1

你显然不是要检查

if i is not None:

i永远不会None（它来自enumerate），而您要确保sLis[i+1]和sLis[i]都不是{{1} }}

立即修正错误是用以下内容替换上述行：

None

更清洁的版本是这样的：

if sLis[i+1] is not None and sLis[i] is not None:

Answer 2

您可以在排序后切除None值，然后不必担心在内循环中识别None：

eOut = {}
for key, lis in eLinks.iteritems():
    eCheck = []
    sLis = sorted(lis)
    sLis = sLis[sLis.count(None):]
    for i, _ in enumerate(sLis[:-1]):
        dif = sLis[i+1] - sLis[i]
        if dif > 20:
            eCheck.append(dif)
            eOut[key] = eCheck

根据您的示例数据，eOut变为：

{'23607015.0': [30, 450, 25, 1330, 120, 285]}

在dict值上执行减法时TypeError NoneType

2 个答案: