Question

我有一个看起来像这样的文件

0181830207709014000015576526S00000140000014000001242017
0052500056661095000015576527S00000950000095000001242017
0157020294103030000015576528S00000300000030000001242017
2397870060994031500015576529S00000315000031500001242017
2466260219154015000015576530S00000150000015000001242017

我需要插入一个名为＆＃34的特定文本;插入一个新行＆＃34;在line2之后，将输出重定向到具有不同文件名的新文件。我如何使用批量编程来解决这个问题。

Answer 1

使用Findstr /N对文件行进行编号

> findstr /N ".*" test.txt
1:0181830207709014000015576526S00000140000014000001242017
2:0052500056661095000015576527S00000950000095000001242017
3:0157020294103030000015576528S00000300000030000001242017
4:2397870060994031500015576529S00000315000031500001242017
5:2466260219154015000015576530S00000150000015000001242017

用For /f循环来解析输出，在冒号处将%%A分隔为数字，将%%B分隔为行内容。如果数字为2，请插入额外的行。

@Echo off
Set "File=Test.txt"
Set "NewFile=TestNew.txt"
(
  For /f "Tokens=1*Delims=:" %%A in (
    'Findstr /N ".*" "%File%"'
  ) Do If %%A Equ 2 (
    Echo:insert me a new line before
    Echo:%%B
    Echo:insert me a new line below
  ) Else (
    Echo:%%B
  )
) >"%NewFile%"

EDIT 改变了后续读者的逻辑。样本输出：

> type TestNew.txt
0181830207709014000015576526S00000140000014000001242017
insert me a new line before
0052500056661095000015576527S00000950000095000001242017
insert me a new line below
0157020294103030000015576528S00000300000030000001242017
2397870060994031500015576529S00000315000031500001242017
2466260219154015000015576530S00000150000015000001242017

使用批处理编程在第2行之后插入特定文本

1 个答案: