Question

此错误很难调试。它也不是经常发生的。请帮忙吗？ substring方法是否可能被破坏？

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 32
        at java.lang.String.substring(String.java:1765)
        at mmk.basej.main(basej.java:186)

Error in line: "tmp1 = filePathShort1.substring(0, 10)"

这是我的代码：

            String tmp = null;              
            String pdf_name = null;
            for (int z = 0; z < list_chek.length; z++) {                
                if (list_chek[z].toString().indexOf("pdf") > 0 | list_chek[z].toString().indexOf("tif") > 0 | list_chek[z].toString().indexOf("jpg") > 0) {
                    String filePath1 = new String();
                    String filePathShort1 = new String();
                    String tmp1 = null;
                    filePath1 = dir + list_chek[z].toString();
                    filePathShort1 = list_chek[z].toString();
                    tmp1 = filePathShort1.substring(0, 10)
                            + filePathShort1.substring(20, filePathShort.indexOf("tsd7")-1)
                            + "_"
                            + filePath1.substring(
                                    filePath1.indexOf("tsd7"), filePath1
                                            .length() - 4);

                    if (name_no_time.equals(tmp1)) {
                        //System.out.println(name_no_time+" ----   "+tmp1);
                        System.out.println("PDF_NAME " + list_chek[z].toString());
                        pdf_name = list_chek[z].toString();
                    }
                    else if ((list_chek[z].toString().indexOf("jpg") > 0) && ((name_no_time + "_1").equals(tmp1))) { 
                        System.out.println("JPG_NAME " + list_chek[z].toString());
                        pdf_name = list_chek[z].toString();
                    }               
                }
            }

Answer 1

filePathShort1 = list_chek[z].toString();
tmp1 = filePathShort1.substring(0, 10)

如果list_chek [z] .toString的长度大于＆lt; 10，然后substring(0, 10)比提供的String长。这是您的索引超出范围的地方。它试图引用超出tmp1范围的元素。如果list_chek [z]＆lt;你将在下一行中遇到同样的问题。 20.在调用子字符串之前，您需要检查字符串长度。

StringIndexOutOfBoundsException：循环中字符串索引超出范围32

1 个答案: