我有以下代码,但是当play = false时,它不控制允许player2滚动骰子的流程。谁能发现错误?基本上,它永远不会达到:RollTwoDiceP2,我无法弄清楚原因。
注意:我曾尝试在RollTwoDiceP1中将播放(布尔变量)设置为false,希望在返回playerturns()函数时,此时它将转到RollTwoDiceP2(Player2转子)。这不起作用
def callmatrix(player1,player2, n):
print("*************LOADING GAME******************")
print("Welcome:", player1,"and", player2)
for i in matrix(n):
print(i)
playing = True
playerturns(player1,player2,playing)
def playerturns(player1,player2,playing):
print(" - - - - - - - - - - ")
print("Press Enter to contnue")
#playing = True
while(playing):
roll=input()
if roll=="r" or "R":
RollTwoDiceP1(player1,player2)
else:
RollTwoDiceP2(player1,player2)
def RollTwoDiceP1(player1,player2):
turn=input("Player 1, it's your turn to roll the dice: Press r to roll:>>>")
#create two variables here and assign them random numbers
die1=random.randint(1,6)
die2=random.randint(1,6)
#add the two die numbers together
roll=die1+die2
#when you are printing an integer, you need to cast it into a string before you printit
print("Player1: You rolled a:", die1, "and a", die2, "which give you a:", roll)
playing = False
playerturns(player1,player2,playing)
def RollTwoDiceP2(player1,player2):
turn=input("Player 2, it's your turn to roll the dice: Press r to roll:>>>")
#create two variables here and assign them random numbers
die1=random.randint(1,6)
die2=random.randint(1,6)
#add the two die numbers together
roll=die1+die2
print("Player2: You rolled a:", die1, "and a", die2, "which give you a:", roll)
playing = True
playerturns(player1,player2,7,playing)
输出:
Continually asks Player 1 to Roll. Prints the result of Player 1s roll (repeat)
这是一个逻辑错误,因此它不是指定问题的副本。
答案 0 :(得分:0)
问题是行if roll=="r" or "R":
。首先,我们评估roll=="r"
,可能是真或假,然后"R"
,始终为真。由于它与or
结合使用,因此该语句始终为true,并且else
分支未执行。将语句更改为if roll == "r" or roll == "R":
或更高if roll.lower() == "r":