我的坏我删除了旧的东西
答案 0 :(得分:0)
我拿出Ajax调用使其变得简单我为非活动服务器添加了新的ul
并添加了新的列表项。
https://jsfiddle.net/0m2xs3ah/5/
$.each(response.results,function(index, value){
if(value.status){
$('#active-servers').append('<li>'+value.server+'</li>');
}else{
$('#inactive-servers').append('<li>'+value.server+'</li>');
}
});
var response = {
"results": [
{
"server": "server04.republic-m.com",
"status": true
},
{
"server": "server06.republic-m.com",
"status": true
},
{
"server": "server06.republic-m.com",
"status": true
},
{
"server": "server17.republic-m.com",
"status": false
},
{
"server": "server18.republic-m.com",
"status": true
},
{
"server": "server20.republic-m.com",
"status": true
},
{
"server": "server21.republic-m.com",
"status": false
},
{
"server": "server25.republic-m.com",
"status": true
}
]
}
$.each(response.results,function(index, value){
if(value.status){
$('#active-servers').append('<li>'+value.server+'</li>');
}else{
$('#inactive-servers').append('<li>'+value.server+'</li>');
}
});
var servers = response.results;
var onlineServers = servers.filter(function(server){
if(server.status){
return (server.status == true);
}
});
var offlineServers = servers.filter(function(server){
if(!server.status){
return (server.status == false);
}
});
console.log(offlineServers)
console.log(onlineServers)
&#13;
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div>
<span>Active</span>
<ul id= "active-servers">
</ul>
</div>
<div>
<span>Inactive</span>
<ul id= "inactive-servers">
</ul>
</div>
&#13;
答案 1 :(得分:0)
我认为你只需要一个if语句来选择div中的结果:
$(document).ready( function() {
$.ajax({
type: 'POST',
url: 'servers',
data: {results:'results', status:'status'},
dataType: 'json',
cache: false,
success: function(response) {
$('#active-servers, #inactive-servers').html('');
$.each(response.results,function(index,result){
if (result.status)
$('#active-servers').append('<li>'+result.server+'</li>');
else
$('#inactive-servers').append('<li>'+result.server+'</li>');
});
}
});
});