在我的ASPNETUsers表中创建“假”用户

时间:2017-02-02 11:04:20

标签: c# asp.net asp.net-mvc asp.net-core integration-testing

我正在运行一些集成测试,我希望在ASPNETUsers表中创建一个“假”用户。

我试图在没有运气的情况下做以下事情。

所以我的设置如下: -

[SetUp]
public void Setup()
{
    var basePath = PlatformServices.Default.Application.ApplicationBasePath;
    var projectPath = Path.GetFullPath(Path.Combine(basePath, "../../../../SportsStore2.Tests"));

    var server = new TestServer(Utils.GetHostBuilder(new string[] { })
        .UseContentRoot(projectPath)
        .UseEnvironment("Development")
        .UseStartup<Startup>());

    _client = server.CreateClient();
}

然后插入如下: -

var registerViewModel = new RegisterViewModel
{
    Email = "test@test.com",
    ConfirmPassword = "testing12345?",
    Password = "testing12345?"
};
_client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

var postResponseASPNETUser = await _client.PostAsJsonAsync("http://localhost:49406/Account/Register", registerViewModel);
var createdASPNETUser = await postResponseASPNETUser.Content.ReadAsStringAsync();

但是我收到了400回复,错误请求。

任何想法我做错了什么?

感谢您的帮助和时间。

1 个答案:

答案 0 :(得分:0)

不是直接调用api,因为我没有运气而且找不到为什么它没有返回正确的响应,我决定走另一条路线,基本上在我的UsersController中创建了另一个Create Action,如下所示: -

    [HttpPost("Create")]
    public IActionResult Create([FromBody] User user)
    {
        if (user == null)
            return BadRequest();

        var result = _usersService.Add(user, m => m.Name == user.Name);
        if (result)
        {
            return CreatedAtRoute("GetUsers", new { id = user.Id }, user);

        }
        return BadRequest("Item not added");
    }

    [HttpPost("CreateAspNetUsers")]
    public IActionResult CreateAspNetUsers([FromBody] RegisterViewModel registerViewModel)
    {
        if (registerViewModel == null)
            return BadRequest();

        var result = _aspNetUsersService.Add(registerViewModel, m => m.Name == registerViewModel.Email);
        if (result)
        {
            return CreatedAtRoute("GetUsers", registerViewModel);
        }
        return BadRequest("Item not added");
    }

这很好,并且给了我我追求的结果。