我在文件filenames.txt中有一个文件名列表。我将逐个打开所有文件，并希望将某些操作的结果写入不同的目录，但文件名相同。到目前为止，我试过这个，但这不会奏效。有什么帮助吗？
with open("/home/morty/filenames.txt","r") as f:
names = [name.strip() for name in f]
for name in names:
save=open("/home/morty/dir/%name" %name,"w")
save.write(---some operation---)
我的问题与此类似，但我不想要通过count / enumerate命名的文件。我希望名称与输入文件名相同： Write output of for loop to multiple files
答案 0 :(得分：1)
您的格式声明不正确。它应该是var webpack = require('webpack');
var webpackDevServer = require('webpack-dev-server');
var webpackConfig = require('../webpack.config.js');
var path = require('path');
var fs = require('fs');
var mainPath = path.resolve(__dirname, '..', 'resources/assets/scripts', 'main.js');
module.exports = function() {
// Fire webpack and run compiler
var bundleStart = null;
var compiler = webpack(webpackConfig);
// Notify console that bundling started
compiler.plugin('compile', function() {
console.log('Bundling...');
bundleStart = Date.now();
});
// Notify when compiling is done
compiler.plugin('done', function() {
console.log('Bundled in ' + (Date.now() - bundleStart) + 'ms!');
});
// Init instance of webpackDevServer
var bundler = new webpackDevServer(compiler, {
publicPath: '/public/',
hot: true,
quiet: false,
noInfo: true,
stats: {
colors: true
}
});
// Start development server and give some notifications in console
bundler.listen(8080, 'localhost', function() {
console.log('Bundling project, please wait...');
});
}
但是当你想加入一个带有文件名的目录名时，最好是这样使用"/home/morty/dir/%s" %name：
os.path.join（以及for name in names:
with open(os.path.join("/home/morty/dir",name),"w") as save:
save.write(---some operation---)
上下文块，以确保文件在完成后关闭）