Question

我有一个组合框：

   <Grid>

    <ComboBox Height="52" HorizontalAlignment="Left"
              ItemsSource="{Binding templatesNames}"
              SelectedValuePath="Type.FullName"         
              Margin="169,43,0,0" Name="comboBox1" 
              VerticalAlignment="Top" Width="148" />

    <Button Content="Button"
   ***Template="{Binding key = Converter={Binding SelectedItem.Value,ElementName=comboBox1}}"
            Height="56" HorizontalAlignment="Left" 
            Margin="191,204,0,0" Name="button1" 
            VerticalAlignment="Top" Width="80" />
</Grid>

问题是使用 * 签署的我有templatesNames如何保存模板的名称我想将这些名称转换为按钮即将绑定到的键（模板键）

我该怎么办？... 转换器应该做什么？它需要吗？我可以不用吗？

编辑：这就是我现在所做的：

    <ComboBox x:Name="ComboBox1"
                              ItemsSource="{Binding collection}" 
                               Margin="553,0,0,13" 
                              SelectedValuePath="Type.FullName" SelectedIndex="1"
                              FontFamily="Buxton Sketch"
                              FontSize="20" HorizontalAlignment="Left" Width="231" Height="46"     VerticalAlignment="Bottom" />

其中集合是公共的ObservableCollection集合{get;组; }

按钮是@Meleak Button的similer，项目命名空间是clr-namespace：dinamicGridLayout 我应该在转换器内写入Uri resourceLocater = new Uri（@“clr-namespace：dinamicGridLayout; ResourceDictionary1.xaml”，System.UriKind.Relative）;？

Answer 1

如果您将所有ControlTemplates放在资源字典中，您可以像这样使用转换器来模板

<ComboBox Height="52" HorizontalAlignment="Left" 
          ItemsSource="{Binding templatesNames}" 
          SelectedValuePath="Type.FullName"          
          Margin="169,43,0,0" Name="comboBox1"  
          VerticalAlignment="Top" Width="148" /> 

<Button Content="Button" 
        Template="{Binding SelectedItem.Value,
                           ElementName=comboBox1,
                           Converter={StaticResource TemplateConverter}}"
        Height="56" HorizontalAlignment="Left"  
        Margin="191,204,0,0" Name="button1"  
        VerticalAlignment="Top" Width="80" />

在转换器中，您从资源字典加载ControlTemplate并将其返回。

public class TemplateConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        string resourceKey = value.ToString();
        Uri resourceLocater = new Uri("/YourNamespace;component/Dictionary1.xaml", System.UriKind.Relative);
        ResourceDictionary resourceDictionary = (ResourceDictionary)Application.LoadComponent(resourceLocater);
        return resourceDictionary[resourceKey] as ControlTemplate;
    }
    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        return null;
    }
}

<强>更新

如果您的命名空间是dinamicGridLayout，那么转换器应该如下所示

Uri resourceLocater = new Uri("/dinamicGridLayout;component/Dictionary1.xaml", System.UriKind.Relative);

小样本项目已上传here。

将combobox选择的值作为另一个控件wpf的dataTemplate的键

1 个答案: