每个json加载中的Jquery.html无法正常工作

时间:2017-02-02 03:43:38

标签: javascript jquery html css json

我使用这个啧啧:https://www.ostraining.com/images/coding/jquery-flip/demo/ 它的工作非常完美。此代码工作正常,它显示带有影响的2图像

<div id="flip">
<div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;">
    <div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
    <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
</div>
<div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;">
    <div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
    <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;">
        <img src="img/source/5.jpg" alt="" style="backface-visibility: hidden;">
    </div>
</div>  
</div>

因为我正在通过json加载数据,所以,我想在循环json加载中加载这个效果,我希望它在有效的数据中显示10个图像,我的代码:

<div id="flip">

</div>
<script>
$(document).ready(function(){
var url="http://localhost/service/load_data.php";
//load 10 image
$.getJSON(url,function(result){
$.each(result, function(i, field){
  var id=field.id;
  var img=field.img;
  $('#flip').append('<div id="flip-this" class="flip-horizontal" style="perspective: 600px; position: relative; transform-style: preserve-3d;"><div class="front" style="height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 1; transition: all 0.5s ease-out; transform: rotateY(0deg);"> <img src="img/source/'+img+'" alt="" style="backface-visibility: hidden;"> </div> <div class="back" style="transform: rotateY(-180deg); height: 100%; width: 100%; backface-visibility: hidden; transform-style: preserve-3d; position: absolute; z-index: 0; transition: all 0.5s ease-out;"> <img src="img/source/'+img+'" alt="" style="backface-visibility: hidden;"> </div></div> ');
});
});
});
</script>

它不显示图像但不起作用。我认为效果在加载json之前运行,所以它不起作用。请帮我。谢谢!

2 个答案:

答案 0 :(得分:0)

您没有初始化插入html后需要执行的插件

这样的东西
$.getJSON(url, function(result) {
  var $flip = $('#flip')
  $.each(result, function(i, field) {
    var id = field.id;
    var img = field.img;
    $flip.append('<div id="flip....../div> ');
  });
  $flip.flip({ /* plugin options here */ })
});

我对这个特定的插件一无所知。

它可能还允许您将图像添加到现有实例。如果是这样,将在文档中列出

答案 1 :(得分:0)

DatabaseReference ref = FirebaseDatabase.getInstance().getReference();
DatabaseReference issue1 = ref.child("issue_1");

myAdapter = new FirebaseListAdapter<Song>(player.this, Song.class,
                                          R.layout.song_item, issue1) {

试试这个,这可能是因为所有函数绑定都在已经加载的元素上 如果要动态加载元素,还需要将函数绑定到新加载的元素。