Question

我试图用这种结构实现一个类：

class type_of_thing():
    def __init__(self, type, code, version, description, year, family):
        self.type = type
        self.code = code
        self.version = version
        self.description = description
        self.year = year
        self.family = family

# with this I would create a new element of this class:

obj_type1 = type_of_thing(type = "x", code = "WRT-001", version= "1-10", description= "custom", year = "2016", family = "class1")
obj_type1_2 = type_of_thing(type = "x", code = "WRT-001", version= "1-11", description= "custom", year = "2016", family = "class1")
obj_type2 = type_of_thing(type = "xy", code = "WRT-001", version= "1-12", description= "custom", year = "2016", family = "class1")

但我必须创建数百个这样的元素，我已经将它们放在这样的列表中：

type of thing1:

type = "x", 
code = "WRT-001", 
version= "1-10", 
description= "custom", 
year = "2016", 
family = "class1"

type = "x", 
code = "WRT-001", 
version= "1-11", 
description= "custom", 
year = "2016", 
family = "class1"

type of thing2:

type = "xy", 
code = "WRT-001", 
version= "1-12", 
description= "custom", 
year = "2016", 
family = "class1"

type = "xy", 
code = "WRT-001", 
version= "1-10", 
description= "custom", 
year = "2016", 
family = "class1"

type of thing3:
...
...
...

让我们说我可以将它们放在这样的列表中：

type_of_thing1 = ["x","WRT-001","1-10","custom","2016","class1"]
type_of_thing1_2 = ["x","WRT-001","1-11","custom","2016","class1"]
type_of_thing2 = ["xy","WRT-001","1-12","custom","2016","class1"]
type_of_thing3 = ["...","...","...","...","..","..."]

所以我试图找到一种pythonic方法来使用类来实现它，并避免创建一堆对象或一堆列表来存储我拥有的所有类型的组合。

像列表一样管理它，按位置访问其元素而不是创建类会更好吗？您认为我可以做些什么来改进我的代码？

Answer 1

假设这些列表是文本字符串，您只需解析该列表并放入dict即可。这是一个例子：

txt='''\
type = "x", 
code = "WRT-001", 
version= "1-10", 
description= "custom", 
year = "2016", 
family = "class1"

type = "x", 
code = "WRT-001", 
version= "1-11", 
description= "custom", 
year = "2016", 
family = "class1"'''

for block in txt.split('\n\n'): 
    di={}
    for line in block.splitlines():
        k,v=[e.strip().strip('"') for e in line.rstrip().rstrip(',').split('=')]
        di[k]=v
    print(di)

打印：

{'type': 'x', 'code': 'WRT-001', 'version': '1-10', 'description': 'custom', 'year': '2016', 'family': 'class1'}
{'type': 'x', 'code': 'WRT-001', 'version': '1-11', 'description': 'custom', 'year': '2016', 'family': 'class1'}

然后使用dict di调用类构造函数。

根据您的修改，您可以执行以下操作：

>>> keys=['type', 'code', 'version', 'description', 'year', 'family']   
>>> vals=["x","WRT-001","1-10","custom","2016","class1"]
>>> {k:v for k,v in zip(keys, vals)}
{'type': 'x', 'code': 'WRT-001', 'version': '1-10', 'description': 'custom', 'year': '2016', 'family': 'class1'}

Answer 2

Python将它的全局变量存储在globals()中，您还提到了一个信息列表，您可以遍历该列表，将类添加到globals()。

list_of_things = [("x","WRT-001","1-10","custom","2016","class1"),
                  ("x","WRT-001","1-11","custom","2016","class1"),
                  ("xy","WRT-001","1-12","custom","2016","class1")]

class type_of_thing():
    def __init__(self, type, code, version, description, year, family):
        self.type = type
        self.code = code
        self.version = version
        self.description = description
        self.year = year
        self.family = family

for i,thing in enumerate(list_of_things):
    globals()["thing_"+str(i)] = type_of_thing(thing[0],thing[1],thing[2],thing[3],thing[4],thing[5])

print(thing_0)

此代码将创建变量名thing_0至thing-<Number of list indicies>，然后打印第一个thing_0。

希望这有帮助！如果它不是你想要的，请告诉我。

另外它不是非常pythonic。：/

谢谢：）

如何实现已创建多个元素的类？

2 个答案: