Question

我对SQL很新，所以请给我一些松懈（哈哈）。我尝试过以下脚本，但出于某种原因，它不起作用？我已经仔细检查了一切，这里的错误在哪里？

$conn = new mysqli('localhost','root','', 'hugh_network') or die("Error in the connect.." . mysqli_error($conn));

$sql = "INSERT INTO accounts (first, last, email, username, password, unid, grp)
VALUES ('$first', '$last', '$email', '$username', '$password', '$unid', '$grp')";

if ($conn->query($sql) === TRUE) {} else {
    die("An error has occured in the database connection. Contact an admin or developer.");
}

$conn->close();

Answer 1

你的代码语法看起来很好，尝试将它包装在try / catch中以防万一我们错过了，并且首先逃避你的所有价值$ $ ....

try {

    $conn = new mysqli('localhost','root','', 'hugh_network') or die("Error in the connect.." . mysqli_error($conn));

    $sql = "INSERT INTO accounts (first, last, email, username, password, unid, grp) VALUES ('$first', '$last', '$email', '$username', '$password', '$unid', '$grp')";

    if ($conn->query($sql) === TRUE) {

    } else {
       die("An error has occured in the database connection. Contact an admin or developer.");
    }
    $conn->close();
  } catch (Exception $e) {
      die($e->getMessage());
  }

或检查数据库的完整性，列名，用户权限或类似内容......

取得联系;）

SQL连接出错，一切看起来都不错？

1 个答案: