Question

我试着从omdb API获取电影标题和信息。这是我的代码：

<?php
$enter = $_GET["enter"];
$content = file_get_contents("https://www.omdbapi.com/?s=$enter&r=xml");

$xml = simplexml_load_string($content);

if($xml) {

echo "<h2>" .$xml->title. "</h2>";

 }
else
{
echo "Nothing found. Add the info manualy";
}
?>

“输入”值来自使用AJAX的搜索表单。他只创建一个空的h2标签。我如何从API中获取数据？

谢谢你，儒略

Answer 1

您应该熟悉xml的结构，以了解如何访问其元素。 print_r(get_object_vars($xml))会向您显示如下结构：

Array
(
    [@attributes] => Array
        (
            [totalResults] => 3651
            [response] => True
        )

    [result] => Array
        (
            [0] => SimpleXMLElement Object
                (
                    [@attributes] => Array
                        (
                            [title] => World War Z
                            [year] => 2013
                            [imdbID] => tt0816711
                            [type] => movie
                            [poster] => https://images-na.ssl-images-amazon.com/images/M/MV5BMTg0NTgxMjIxOF5BMl5BanBnXkFtZTcwMDM0MDY1OQ@@._V1_SX300.jpg
                        )

                )

            [1] => SimpleXMLElement Object
                (
                    [@attributes] => Array
                        (
                            [title] => Captain America: Civil War
                            [year] => 2016
                            [imdbID] => tt3498820
                            [type] => movie
                            [poster] => https://images-na.ssl-images-amazon.com/images/M/MV5BMjQ0MTgyNjAxMV5BMl5BanBnXkFtZTgwNjUzMDkyODE@._V1_SX300.jpg
                        )

                )

            ...
            ...
            ...  

            [9] => SimpleXMLElement Object
                (
                    [@attributes] => Array
                        (
                            [title] => War
                            [year] => 2007
                            [imdbID] => tt0499556
                            [type] => movie
                            [poster] => https://images-na.ssl-images-amazon.com/images/M/MV5BMTgzNTA4MTc3OF5BMl5BanBnXkFtZTcwOTA0ODk0MQ@@._V1_SX300.jpg
                        )

                )

        )

)

因此，您会收到一个数组，其中包含您需要选择的结果。或者，如果您知道API具有t=title选项的确切标题，该选项仅返回单个结果（请参阅documentation）。

因此，假设您使用返回多个结果的s=title选项，您可以使用类似的内容从第一个结果中选择信息：

<?php
$enter = $_GET["enter"];
$content = file_get_contents("https://www.omdbapi.com/?s=$enter&r=xml");

$xml = simplexml_load_string($content);

# show the structure of the xml
# print_r(get_object_vars($xml));

if($xml) {
    print "<h2>" .$xml->result[0]['title']. "</h2>";
    print "<br>imdbID=" . $xml->result[0]['imdbID'] ;
} else {
    echo "Nothing found. Add the info manualy";
}
?>

使用xml

1 个答案: