使用HttpClient调用xml内容

时间:2017-02-01 16:58:05

标签: c# xml httpclient

如何使xml内容与内容的HttpClient's PostAsync操作兼容,并在何处为headers指定Content-Type = application/xml

错误 - >无法将字符串转换为HttpContent

public async Task GetCustomersAsync(string firstname, string lastname)
{
        using (var client = new HttpClient())
        {
            var content = "<soapenv:Envelope xmlns:xsi...";

            var response = await client.PostAsync("https://domain.com/scripts/WebObj.exe/Client.woa/2/ws/ABC", content);

            var responseString = await response.Content.ReadAsStringAsync();
        }
    }

2 个答案:

答案 0 :(得分:1)

我的猜测是你想要做的是以下几点:

public async Task<string> GetCustomersAsync(string firstname, string lastname)
{
    using (var client = new HttpClient())
    {
        var content = new StringContent("<soapenv:Envelope xmlns:xsi...", Encoding.UTF8, "application/xml");;

        var response = await client.PostAsync("https://example.com/scripts/WebObj.exe/Client.woa/2/ws/ABC", content);

        return await response.Content.ReadAsStringAsync();
    }
}

OR

using (var request = new HttpRequestMessage { RequesteUri = new Uri("POST_URL"), Method = HttpMethod.Post })
{
    var content = new StringContent("<soapenv:Envelope xmlns:xsi...");
    request.Content.Headers.ContentType = new MediaTypeHeaderValue("application/xml");
}

您可以refer here获取有关可以创建和传递的其他内容类型的更多信息。

答案 1 :(得分:1)

要专门请求xml内容作为响应,您必须在内容的标题中定义内容类型。在内容标题的ContentType属性中解析并设置MediaTypeHeaderValue。这是代码的完整示例;

using (var client = new HttpClient())
{
    var content = new StringContent(messageToPOST, Encoding.UTF8, "text/xml");
    content.Headers.ContentType = MediaTypeHeaderValue.Parse("text/xml");
    response = await client.PostAsync(_uri, content);
    responseMsg = await response.Content.ReadAsStringAsync();
}

可以将请求作为响应返回的responseMsg属性解析为字符串,或者使用诸如

这样的表达式转换为xml并验证为xml
XDocument xdoc = XDocument.Parse(responseMsg);
string xmlAsString = xdoc.ToString();