Question

尝试从我的服务器构建JSON响应时遇到问题。

我想获得一个包含其他JSON对象的JSON对象，这些对象是我从SQL查询中获得的，因此我可以通过我的websocket服务器发送包含JSON的文件

直到现在我尝试过这样的事情：

    def screenColor(self,ne_Lat, ne_Lng, sw_lat, sw_Lng):
    data={}
    allData=[]
    for rec in self.c.execute('''SELECT * FROM squares WHERE ((lat BETWEEN ? AND ?) AND (long BETWEEN ? AND ?)) ''',(sw_lat, ne_Lat, sw_Lng, ne_Lng)):
          data['color']=rec[3]
          data['lat']=rec[1]
          data['lng']=rec[2]
          json_data=json.dumps(data)
          allData.append(json_data)
    return allData

当我打印返回的值时，我得到：

['{"color": 85, "lat": 31.776879500000156, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.778179500000157, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.779479500000157, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.780779500000158, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.782079500000158, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.78337950000016, "lng": 35.21187200000153}', '{"color": 26, "lat": 31.78467950000016, "lng": 35.21187200000153}', '{"color": 28, "lat": 31.78597950000016, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.78727950000016, "lng": 35.21187200000153}', '{"color": 85, "lat": 31.776879500000156, "lng": 35.21367200000153}', '{"color": 28, "lat": 31.778179500000157, "lng": 35.21367200000153}', '{"color": 85, "lat": 31.779479500000157, "lng": 35.21367200000153}', '{"color": 26, "lat": 31.780779500000158, "lng": 35.21367200000153}', '{"color": 26, "lat": 31.782079500000158, "lng": 35.21367200000153}', '{"color": 26, "lat": 31.78337950000016, "lng": 35.21367200000153}', '{"color": 85, "lat": 31.78467950000016, "lng": 35.21367200000153}

是否有办法将此数组作为JSON对象？那已经是JSON对象吗？

非常感谢！

Answer 1

您应该尝试以下方法：

def screenColor(self,ne_Lat, ne_Lng, sw_lat, sw_Lng):

    allData=[]
    for rec in self.c.execute('''SELECT * FROM squares WHERE ((lat BETWEEN ? AND ?) AND (long BETWEEN ? AND ?)) ''',(sw_lat, ne_Lat, sw_Lng, ne_Lng)):
          data = {}
          data['color']=rec[3]
          data['lat']=rec[1]
          data['lng']=rec[2]

          allData.append(data)
    return json.dumps(allData)

否则，如果你在循环之外定义你的字典data，它会在每次迭代时被覆盖我猜...

在python中编写嵌套的json

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