Question

我有字符串，我需要在每\n之后将其拆分为新行。这在以下代码中成功完成：

  #include <iostream>
  #include <QtCore>

  int main(int argc, char ** argv)
   {
        QString myString("diskinfo: Node,Description,FreeSpace,Name,Size  \nASHUTOSH-PC,Local Fixed Disk,420935663616,C:,499875049472  \nASHUTOSH-PC,CD-ROM Disc,,D:,  \nASHUTOSH-PC,Local Fixed Disk,324989792256,E:,487687450624  \nASHUTOSH-PC,CD-ROM Disc,0,F:,553459712");

        QStringList myStringList = myString.split("\n");


       for(int index =0;index < myStringList.length();index++)
           {
             std::cout<<myStringList.at(index).toStdString()<<std::endl;
           }
        }

上述代码的输出是：

    Node,Description,FreeSpace,Name,Size
    OSH-PC,Local Fixed Disk,420942745600,C:,499875049472
    OSH-PC,CD-ROM Disc,,D:,
    OSH-PC,Local Fixed Disk,324861591552,E:,487687450624
    OSH-PC,CD-ROM Disc,0,F:,553459712

现在接下来我要做的是：

获取以下输出如何完成：

   Node: OSH-PC Description:Local Fixed Disk, FreeSpace:420942745600, Name:C:,size:499875049472
   Node: OSH-PC Description:CD-ROM, FreeSpace:, Name:D:,size:,

在Qt c ++中这怎么可能？

Answer 1

好吧，你只需要用＆＃34;，＆＃34;分割QStringList的内部字符串（因为它们是QStrings）。分隔符，然后使用基本串联将分割的数据与分割的描述（QStringList的第一个元素）连接在一起。这是我的建议：

QStringList myStringList = myString.split("\n");

QStringList descriptions = myStringList[0].split(",");
descriptions[0] = descriptions[0].remove(0, descriptions[0].indexOf(" ") + 1);

for(int index = 1;index < myStringList.length();index++)
{
    QStringList data = myStringList[index].split(",");
    QStringList out;
    for(int ind_2 = 0; ind_2 < data.length(); ind_2++)
        out.push_back(descriptions[ind_2] + ": " +data[ind_2]);
    QString out_str = out.join(", ");
    std::cout << out_str.toStdString() << std::endl;
}

JFF，c ++ 11-heavy version：）

#include <iostream>
#include <QtCore>
#include <algorithm>
#include <vector>

int main(int argc, char ** argv)
{
    QString myString("diskinfo: Node,Description,FreeSpace,Name,Size  \nASHUTOSH-PC,Local Fixed Disk,420935663616,C:,499875049472  \nASHUTOSH-PC,CD-ROM Disc,,D:,  \nASHUTOSH-PC,Local Fixed Disk,324989792256,E:,487687450624  \nASHUTOSH-PC,CD-ROM Disc,0,F:,553459712");

    QStringList myStringList = myString.split("\n");

    QStringList descriptions = myStringList[0].split(",");
    descriptions[0] = descriptions[0].remove(0, descriptions[0].indexOf(" ") + 1);

    std::vector<QStringList> data;
    std::transform(myStringList.begin() + 1, myStringList.end(), std::back_inserter(data), [](QString& data_string) {
        return data_string.split(",");
    });

    QStringList out_data;
    std::transform(data.begin(), data.end(), std::back_inserter(out_data), [&descriptions](QStringList& list) {
        QStringList with_desc;
        for(size_t i = 0; i < list.size(); i++)
            with_desc.push_back(descriptions[i] + ": " + list[i]);
        return with_desc.join(",");
    });

    std::cout << out_data.join("\n").toStdString() << std::endl;
}

Answer 2

这看起来像商业逻辑，如果您熟悉Multitier Architecture，您就会意识到将其与表示层分开的重要性。

在这种情况下，这是一件非常好的事情，因为您会发现c++11使用vector<vector<string>>将sregex_token_iterator分成const regex re{ "((?:[^\\\\,]|\\\\.)+)(?:,|$)" }; vector<vector<string>> descriptions; for (auto it = cbegin(myStringList); it != cend(myStringList); ++it) descriptions.emplace_back(vector<string>{ cregex_token_iterator(it->cbegin(), it->cend(), re, 1), cregex_token_iterator() }); for (auto i = 1; i < size(descriptions); ++i) { for (auto j = 0; j < size(descriptions.front()) - 1; ++j) { cout << descriptions.front()[j] << ": " << descriptions[i][j] << ",\t"; } cout << descriptions.front().back() << ": " << descriptions[i].back() << endl; }非常简单：

if (glob(...))

Live Example

我在my comment中提到您输入的字符串与输出字符串不匹配。对于我的代码，我要求在每个分隔符之间至少有一个空白字符（＆＃39;，＆＃39;）。

使用＆＃39; \ n＆＃39;拆分数据qt中的字符

2 个答案: