Question

我是Python的新用户，我正在尝试循环以下内容：

text = open('filename.txt', 'rU').read()  
splitter = Splitter()
postagger = POSTagger()
splitted_sentences = splitter.split(text)
pos_tagged_sentences = postagger.pos_tag(splitted_sentences)
dicttagger = DictionaryTagger([ 'dicts/positive.yml', 'dicts/negative.yml'])
dict_tagged_sentences = dicttagger.tag(pos_tagged_sentences)
scoreposneg = sentiment_score(dict_tagged_sentences)
dicttagger = DictionaryTagger([ 'dicts/positive.yml', 'dicts/negative.yml', 'dicts/inc.yml', 'dicts/dec.yml', 'dicts/inv.yml'])
dict_tagged_sentences = dicttagger.tag(pos_tagged_sentences)
scoretotal = sentiment_total(dict_tagged_sentences)
print scoretotal

在此之前，我已经为Splitter，POSTagger，DictionaryTagger，sentiment_total设置了类，还创建了5个不同的词典。当我在Python上运行1个filen时，这是有效的（我从print scoretotal获得了一个数字）。但是，当我尝试创建一个循环并打印所有输出（我的目录中有650个文件）时，它不起作用（没有打印）并且scoretext.txt文件中有0.0个。

path = '/mydirectory'
files = glob.glob(path)
for file in files:
    text = open(file, 'rU').read()
    splitter = Splitter()
    postagger = POSTagger()
    splitted_sentences = splitter.split(text)
    pos_tagged_sentences = postagger.pos_tag(splitted_sentences)
    dicttagger = DictionaryTagger([ 'dicts/positive.yml', 'dicts/negative.yml'])
    dict_tagged_sentences = dicttagger.tag(pos_tagged_sentences)
    scoreposneg = sentiment_score(dict_tagged_sentences)
    dicttagger = DictionaryTagger([ 'dicts/positive.yml', 'dicts/negative.yml', 'dicts/inc.yml', 'dicts/dec.yml', 'dicts/inv.yml'])
    dict_tagged_sentences = dicttagger.tag(pos_tagged_sentences)
    scoretotal = sentiment_total(dict_tagged_sentences)
    print scoretotal

scoretotal = np.zeros((1,650))
scoretotal_no = 0
scoretotal_no = scoretotal_no + 1

np.savetxt("scoretext.txt", scoretotal, delimiter=" ", fmt="%s")

如果有人可以就此提供一些见解，我们将非常感激。谢谢！

Answer 1

您的问题可能是您访问目录中的文件的方式。看到这个： Use a Glob() to find files recursively in Python?

如何在数组中循环，打印和保存输出

1 个答案: