我在下面写了使用路径弧命令制作椭圆。但我正在使用A arc命令。我想切换到function getEclipsePath(start, end) {
var rx = (end.x - start.x) * 0.5;
var ry = (end.y - start.y) * 0.5;
var d = rx * 2;
return "M " + start.x + " " + (start.y + ry) + " a " + rx + " " + ry + " 0 1 1 " + d + " 0 a " + rx + " " + ry + " 0 1 1 " + -d + " 0 z";
}
var str = getEclipsePath(100, 100, 70, 50);
var test = document.getElementById('test');
var point;
document.addEventListener('mousedown', function(event) {
point = {
x: event.clientX,
y: event.clientY
}
});
document.addEventListener('mousemove', function(event) {
var target = {
x: event.clientX,
y: event.clientY
}
if (point) {
var str = getEclipsePath(point, target);
document.getElementById('test').setAttribute('d', str);
}
});
document.addEventListener('mouseup', function(event) {
point = null;
});命令。因为它取决于相对（假设是错误的评论）位置
我尝试给出直径值，但它产生随机形状。请帮我改一下。
body,
html {
height: 100%;
width: 100%;
margin: 0;
padding: 0
}
svg {
height: 100%;
width: 100%
}<svg>
<path id="test" d="
M 0 0
a 20,10 0 1,1 40,0
a 20,10 0 1,1 -40,0
" />
</svg>$('#' + tableId).find("[id='" + childEl + "']").addClass('highlight');
// ------------------------^---------------^