Question

我需要增加字母，我需要将字母与组合匹配。

var allArrays = new Array(['a','c'],['b','e'],['r','s']);

function getPermutation(array, prefix) {
    prefix = prefix || '';
    if (!array.length) {
        return prefix;
    }

    var result = array[0].reduce(function (result, value) {
        return result.concat(getPermutation(array.slice(1), prefix + value));
    }, []);
    return result;
}

console.log(getPermutation(allArrays));

其中['a'，'c']

a，b，r ---＆gt;从位置

c，e，s ---＆gt;到位置

对于剩余的数组也是如此。

我需要输出

"abr","abs","acr","acs","adr","ads","aer","aes","bbr","bbs","bcr","bcs","bdr","bds","ber","bes","cbr","cbs","ccr","ccs","cdr","cds","cer","ces"

但我得到的输出就像这样，

"abr","abs","aer","aes","cbr","cbs","cer","ces"

我只是在它们之间获得组合，但我正在努力增加所给出的字母，并且必须做组合。

Answer 1

您可以先填补空白，然后应用getPermutation。

function getPermutation(array, prefix) {
    prefix = prefix || '';
    if (!array.length) {
        return prefix;
    }

    var result = array[0].reduce(function (result, value) {
        return result.concat(getPermutation(array.slice(1), prefix + value));
    }, []);
    return result;
}

var allArrays = new Array(['a', 'c'], ['b', 'e'], ['r', 's']);

allArrays.forEach(function (a) {
    var value = parseInt(a[0], 36) + 1,
        last = a.pop(),
        lastValue = parseInt(last, 36);
  
    while (value <= lastValue) {
        a.push(value.toString(36));
        value++;
    }
});

console.log(allArrays);
console.log(getPermutation(allArrays));

.as-console-wrapper { max-height: 100% !important; top: 0; }

字母和任何数字的解决方案，无论顺序如何，都要检查类型并使用变量来递增/递减值。

function getPermutation(array, prefix) {
    prefix = prefix || '';
    if (!array.length) {
        return prefix;
    }

    return array[0].reduce(function (result, value) {
        return result.concat(getPermutation(array.slice(1), prefix + value));
    }, []);
}

var allArrays = new Array(['a', 'c'], ['e', 'b'], ['02', '04'], ['32', '29']);

allArrays.forEach(function (a) {
    var length = a[1].length,
        pad = isNaN(a[0]) ? ' ' : '0',
        radix = isNaN(a[0]) ? 36 : 10,
        value = parseInt(a[0], radix),
        lastValue = parseInt(a.pop(), radix),
        inc = +(lastValue >= value) || -1,
        temp;

    value += inc;
    while (inc === 1 ? value <= lastValue : value >= lastValue) {
        temp = value.toString(radix);
        while (temp.length < length) {
            temp = pad + temp;
        }
        a.push(temp);
        value += inc;
    }
});

console.log(allArrays);
console.log(getPermutation(allArrays));

.as-console-wrapper { max-height: 100% !important; top: 0; }

在jquery中增加值的两个字符串的组合

1 个答案: