我尝试使用getHours和getMinutes在以后的函数中使用它们。问题是我总是希望最终的数字是3或4位和2位数。当分钟为0-9时,1:04的结果为14,会发生什么。这是我的代码,它不能解决问题。
$hours = (new Date).getHours(),
$mins = (new Date).getMinutes();
function addZero($hours) {
if ($hours < 10) {
$hours = "0" + $hours;
}
return $hours;
}
function addZero($mins) {
if ($mins < 10) {
$mins = "0" + $mins;
}
return $mins;
}
$nowTimeS = $hours + "" + $mins;
// Convert string with now time to int
$nowTimeInt = $nowTimeS;
答案 0 :(得分:1)
问题是您有两个具有相同名称的功能,但您从不调用该功能:
$date = new Date();
$hours = $date.getHours(),
$mins = $date.getMinutes();
$nowTimeS = addZero($hours) + "" + addZero($mins);
// Convert string with now time to int
$nowTimeInt = $nowTimeS;
function addZero($time) {
if ($time < 10) {
$time = "0" + $time;
}
return $time;
}
答案 1 :(得分:0)
您使用相同的名称定义了您的函数两次,从未调用它
也许你在找这个?
function pad(num) {
return ("0"+num).slice(-2);
}
var d = new Date(),
hours = d.getHours(),
mins = d.getMinutes(),
nowTimeS = pad(hours) + ":" + pad(mins);
console.log(nowTimeS)
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