我想从this获得this JSON输出。遗憾的是,json_encode()函数不会将数组编码为该格式。根本没有任何回报。这是我的代码。
$output = array(
'responseData' => array(),
'responseDetails' => null,
'responseStatus' => 200
);
$x = 0;
while ($row = mysqli_fetch_assoc($result)) {
foreach ($row as $k => $v) {
$output['responseData']['result'][$x][$k] = $v;
}
$x++;
}
print_r($output);
header('Content-Type: application/json');
echo json_encode($output , JSON_FORCE_OBJECT);
我无法找到原因。有人请帮我找到解决方案。
编辑:抱歉。这是输出 -
预期的JSON输出 -
{
"responseData": {
"results": [{
"qid": 1,
"qtitle": "When do we finish this project ?",
"qimage_url": "http://www.wearesliit.com/example.png",
"user": "samith",
"date": "2016-01-01T02:15:12.356Z",
"type": 1,
"category": 5,
"tags": ["common_senese", "truth", "bazsa_awsanna"],
"note": "Sample quetion"
}, {}, {}]
},
"responseDetails": null,
"responseStatus": 200 }
我根本没有得到任何JSON输出。但这是数组的print_r结果。
Array(
[responseData] => Array
(
[result] => Array
(
[0] => Array
(
[question_ID] => 1
[question_Title] => Which shape does not belong with the other three shapes?
[question_Image_URL] => http://www.wearesliit.com/images/quiz/questions/1.jpg
[quetion_Note] => Easy IQ question.
[category_ID] => 7
[username] => samith
[added] => 2017-01-29 21:50:52
)
[1] => Array
(
[question_ID] => 2
[question_Title] => Tim earns $10 per hour at his job. When he gets paid on Friday, he is paid for 40 hours of work. He then goes out and spends 10% of his earnings on entertainment that weekend. How much money is he left with on Monday?
[question_Image_URL] =>
[quetion_Note] => Easy IQ question.
[category_ID] => 7
[username] => samith
[added] => 2017-01-29 21:50:52
)
)
)
[responseDetails] =>
[responseStatus] => 200 )
答案 0 :(得分:6)
感谢@awiebe,我发现了确切的错误。它的
格式错误的UTF-8字符,可能编码错误
谢谢大家,我从另一个问题找到了解决方案。 'Malformed UTF-8 characters, possibly incorrectly encoded' in Laravel
答案 1 :(得分:3)
json_encode()函数返回“false”。请参阅:http://php.net/manual/en/function.json-encode.php 处理此类问题的最佳方法是使用json_last_error_msg()方法并根据找到的错误执行操作。见:http://php.net/manual/en/function.json-last-error-msg.php。 一个例子是:
$show_json = json_encode($output , JSON_FORCE_OBJECT);
if ( json_last_error_msg()=="Malformed UTF-8 characters, possibly incorrectly encoded" ) {
$show_json = json_encode($API_array, JSON_PARTIAL_OUTPUT_ON_ERROR );
}
if ( $show_json !== false ) {
echo($show_json);
} else {
die("json_encode fail: " . json_last_error_msg());
}
问题是,如果问题是编码字符,则不会显示。只是希望角色对你的工作不是必不可少的,或者如果你能在zigazillion字符串列表中找到不匹配输入,那就纠正它吧。其他类型的错误可以在这里找到:http://php.net/manual/en/json.constants.php。只需对您发现的错误应用if语句和更正。
我希望这有助于某人。
答案 2 :(得分:0)
删除
header('Content-Type: application/json');
请记住,在发送任何实际输出之前,必须通过普通HTML标记,文件中的空行或PHP来调用header()。使用include或require,函数或其他文件访问函数读取代码是一个非常常见的错误,并且在调用header()之前输出空格或空行。使用单个PHP / HTML文件时存在同样的问题。
来自的和JSON_FORCE_OBJECT
echo json_encode($output , JSON_FORCE_OBJECT);
答案 3 :(得分:0)
我想向您介绍这个问题, 在link上 我建议您使用像这样的json_encode包装器:
function safe_json_encode($value){
if (version_compare(PHP_VERSION, '5.4.0') >= 0) {
$encoded = json_encode($value, JSON_PRETTY_PRINT);
} else {
$encoded = json_encode($value);
}
switch (json_last_error()) {
case JSON_ERROR_NONE:
return $encoded;
case JSON_ERROR_DEPTH:
return 'Maximum stack depth exceeded'; // or trigger_error() or throw new Exception()
case JSON_ERROR_STATE_MISMATCH:
return 'Underflow or the modes mismatch'; // or trigger_error() or throw new Exception()
case JSON_ERROR_CTRL_CHAR:
return 'Unexpected control character found';
case JSON_ERROR_SYNTAX:
return 'Syntax error, malformed JSON'; // or trigger_error() or throw new Exception()
case JSON_ERROR_UTF8:
$clean = utf8ize($value);
return safe_json_encode($clean);
default:
return 'Unknown error'; // or trigger_error() or throw new
Exception();
}
}
function utf8ize($mixed) {
if (is_array($mixed)) {
foreach ($mixed as $key => $value) {
$mixed[$key] = utf8ize($value);
}
} else if (is_string ($mixed)) {
return utf8_encode($mixed);
}
return $mixed;
}
在定义了这些功能之后,您可以直接使用它,
echo safe_json_encode($response);