我正在尝试获取,存储并依次使用objectGUID来查询Active Directory。 获取用户属性我正在使用
public static class MyDnKeyValueAttMapper implements AttributesMapper<Object> {
@Override
public List<LdapKeyValueList> mapFromAttributes(Attributes attributes)
throws NamingException, javax.naming.NamingException {
List<LdapKeyValueList> attributeKeyValMap = new ArrayList<LdapKeyValueList>();
NamingEnumeration<String> namingEnumeration = attributes.getIDs();
while (namingEnumeration.hasMoreElements()) {
String attributeName = (String) namingEnumeration.nextElement();
String AttributeValue = attributes.get(attributeName).get().toString();
attributeKeyValMap.add(new LdapKeyValueList(attributeName, AttributeValue));
}
return attributeKeyValMap;
}
}
objectGuid似乎总是以字符串格式返回。 我也试过 -
UUID guid = (UUID) attributes.get("objectGUID").get();
抛出“无法将字符串转换为uuid”
的错误似乎之前我可以做任何事情ldaptemplate搜索总是以字符串格式返回属性。
如何以其格式获取“objectGUID”,以便我可以存储它并在ldapTemplate搜索查询中使用。
提前致谢。
答案 0 :(得分:3)
对于Spring,将“ java.naming.ldap.attributes.binary”属性注入ldapTemplate
@Bean
public LdapTemplate ldapTemplate() {
return new LdapTemplate(contextSource());
}
@Bean
public ContextSource contextSource() {
final LdapContextSource contextSource = new LdapContextSource();
contextSource.setUrl(env.getRequiredProperty("ldap.url"));
contextSource.setBase(env.getRequiredProperty("ldap.base"));
contextSource.setUserDn(env.getRequiredProperty("ldap.user"));
contextSource.setPassword(env.getRequiredProperty("ldap.password"));
// Important!!! Tell ldapTemplate to retrieve AD field
// "objectGUID" as binary. Otherwise it will be
// retrieved as a String, thus, modifying the byte[] array
final Map<String, Object> envProps = new HashMap<>();
envProps.put("java.naming.ldap.attributes.binary","objectGUID");
contextSource.setBaseEnvironmentProperties(envProps);
return contextSource;
}
...
// Will not complain about the String to byte[] conversion and
// Has to be 16 in length. If not, you did something
// wrong. For example ldapTemplate still retrieves objectGUID
// as String, modifying the value
byte[] guidBytes = (byte[]) attributes.get("objectGUID").get();
if (guidBytes.length == 16) {
// Convert encoded AD objectGUID to UUID
// objectGUID is not storing bits sequentially, so do the dance
UUID uuid = UUID.fromString(
String.format("%02x%02x%02x%02x-%02x%02x-%02x%02x-%02x%02x-%02x%02x%02x%02x%02x%02x",
guidBytes[3] & 255,
guidBytes[2] & 255,
guidBytes[1] & 255,
guidBytes[0] & 255,
guidBytes[5] & 255,
guidBytes[4] & 255,
guidBytes[7] & 255,
guidBytes[6] & 255,
guidBytes[8] & 255,
guidBytes[9] & 255,
guidBytes[10] & 255,
guidBytes[11] & 255,
guidBytes[12] & 255,
guidBytes[13] & 255,
guidBytes[14] & 255,
guidBytes[15] & 255));
}
答案 1 :(得分:2)
如果您不希望将二进制属性(objectGUID具有Octet String语法)作为字符串检索,则必须这样说。使用Spring,您必须将<entry key="java.naming.ldap.attributes.binary" value="objectGUID"/>
添加到您的上下文环境中。
稍后byte[] guid = (byte[]) namingEnumeration.getAttributes().get("objectGUID").get();
应该返回您要查找的内容。
刚打字,未经过测试。