它似乎在MakeData函数中,因为这是打破执行的原因。我不确定为什么这不起作用,因为我的导师和我的许多同学的执行几乎相同而且很好。我知道这个代码几乎完全相同的版本,带有Windows文件名,也不能在Windows上运行。我编译了代码。我已经运行了调试器。什么都没有出现。我运行的调试器刚刚运行代码,直到任何非常模糊的错误出现,或者它实际上表明进程处于某种无限循环中。任何帮助将不胜感激!
/*
*Program Description:A program to sort a series of strings and scores from a file.
*
*Programmer:Timothy A. Gass
*Date:01/17/17
*/
#include <iostream>
#include <string>
#include <math.h>
#include <fstream>
#include <vector>
#include <ctime>
using namespace std;
void makeData(string);
void getData(vector<string> &, vector<int> &, string);
int main(){
srand(time(0));
string fname = "/home/tim/dev/c++/chpt9/data.txt";
vector<string> name;
vector<int> score;
makeData(fname);
getData(name, score, fname);
for(int i = 0; i < score.size(); i++){
cout << score[i] << endl;
cout << name[i] << endl;
}
cout << "Press enter to exit." << endl;
cin.ignore();
cin.get();
return 0;
}
void makeData(string fname){
int rand1, rand2, rand3;
const int SCORE_MAX_SIZE = 100;
ofstream make(fname);
const int PEOPLE_NUM = 50;
vector<string> firstNames = {
"Gus",
"Taneka",
"Shane",
"Rosella",
"Bennett",
"Filiberto",
"Khadijah",
"Mafalda",
"Rusty",
"Janiece",
"Shavonne",
"Azalee",
"Enedina",
"Heidy",
"Lavelle",
"Darleen",
"Ashton",
"Glynis",
"Gale",
"Norene",
"Madaline",
"Elvin",
"Jacqueline",
"Kristofer",
"Zachary",
"Lorretta",
"Jim",
"Shanelle",
"Tonja",
"Alethia",
"Kasha",
"Katheleen",
"Joyce",
"Kirstin",
"Neil",
"Belkis",
"Maisha",
"Doretha",
"Eliseo",
"Rhiannon",
"Annamarie",
"Latoria",
"Jerica",
"Betsey",
"Delinda",
"Pamula",
"Porsha",
"Fredia",
"Wilda",
"Belen"
};
vector<string> lastNames = {
"Best",
"Shields",
"Finley",
"Blankenship",
"Hobbs",
"Nichols",
"Mcneil",
"Robles",
"Moyer",
"Hays",
"Elliott",
"Ruiz",
"Ritter",
"Gamble",
"Zamora",
"Cole",
"Larson",
"Ibarra",
"Choi",
"Santana",
"Gray",
"Crane",
"Campos",
"Wright",
"Morris",
"Flores",
"Newman",
"Santos",
"Li",
"Archer",
"Chavez",
"Avery",
"Mora",
"Liu",
"Lutz",
"Miles",
"Stewart",
"Austin",
"Wu",
"Turner",
"Brennan",
"Ferrell",
"Mcmillan",
"Whitney",
"Odonnell",
"Conley",
"Maxwell",
"Stafford",
"Carlson",
"Peck"
};
for(int i = 0; i < PEOPLE_NUM; i++){
rand1 = rand()%50;
rand2 = rand()%50;
rand3 = rand()%(SCORE_MAX_SIZE+1);
make << firstNames.at(rand1) + " " + lastNames.at(rand2) << endl;
make << rand3 << endl;
}
}
void getData(vector<string> &name, vector<int> &score, string fname){
ifstream get(fname);
string str;
int num;
if(get.fail()){
cout << "File could not be opened!" << endl;
}
else
{
while(!get.eof())
{
getline(get, str);
get >> num;
cin.ignore();
name.push_back(str);
score.push_back(num);
}
}
}
答案 0 :(得分:0)
欣欣的评论是正确的。事实证明,getline和cin的使用导致某种形式的无限循环会占用内存,直到计算机最终崩溃。我仍然不知道为什么没有解决方案,或者为什么一起使用cin和getline会产生如此可怕的后果,特别是考虑到确实没有错误代码。即便如此,在getData函数中用getline替换cin然后转换回整数会产生一个干净的程序。