Question

Hi Guys [Java and Android新手]

我有一个php脚本，它会发出像这样的json响应

echo json_encode(array($camparray));

json数组就像这样

[
    {
        "0":{"url":"10007.jpg","cmpname":"Romain Jerome"},
        "2":{"url":"10023.jpg","cmpname":"NGO"},
        "3":{"url":"10024.jpg","cmpname":"Save The Children"},
        "4":{"url":"10039.jpg","cmpname":"John Deere"},
        "5":{"url":"10039.jpg","cmpname":"Starbucks"}
    }
]

现在我正在使用凌空来获得回复。我在某种程度上无法迭代数组。请帮忙..

@Override
public void onResponse(JSONObject response) {
    Toast.makeText(getApplicationContext(),"On Response Try block",Toast.LENGTH_SHORT).show();
    try {
        JSONArray camps = response.getJSONArray("camparray");
        // insert for loop here...
        //String pinusers = response.getString("mobileno");
        //Toast.makeText(getApplicationContext(),"On Response Try block"+pinusers,Toast.LENGTH_SHORT).show();

        if(camps!= null){
            JSONObject jsonObj = new JSONObject("camps");
            JSONArray cmpz = jsonObj.getJSONArray("camparray");
            for (int i = 0; i < cmpz.length(); i++) {
                JSONObject c = cmpz.getJSONObject(i);

                String id = c.getString("url");
                String name = c.getString("cmpname");
                Toast.makeText(getApplicationContext(),"On Response Try bitch"+id+name,Toast.LENGTH_SHORT).show();
            }
        }
        else {
            Toast.makeText(getApplicationContext(),"Camp NULL",Toast.LENGTH_SHORT).show();
        }
    }
    catch (JSONException e) {
        e.printStackTrace();
        Toast.makeText(getApplicationContext(),"Try Fail NULL",Toast.LENGTH_SHORT).show();
    }
}

我不明白为什么它已经过了几个小时而且我无法破解它。我想有些概念问题......

Answer 1

首先，您对服务器的响应采用错误的结构化格式。仍然，要获取此响应的内容，您可以使用此：

  if(camps!= null){
        JSONArray cmpz = new JSONArray("camparray");
        JSONObject jsonObj = cmpz.getJSONObject(0);

        String zero = jsonObj.getString("0");
        JSONObject vZero = new JSONObject(zero);
        String zeroUrl = vZero.getString("url");
        String cmpnameZero = vZero.getString("cmpname");

        String two = jsonObj.getString("2");
        JSONObject vTwo = new JSONObject(two);
        String twoUrl = vTwo.getString("url");
        String cmpnameTwo = vTwo.getString("cmpname");



        String three = jsonObj.getString("3");
        JSONObject vThree = new JSONObject(three);
        String threeUrl = vThree.getString("url");
        String cmpnamTthree = vThree.getString("cmpname");

        //Similarly get value for 4 and 5 and do whatever you want with those variables
    }

java中的json数组/对象迭代

1 个答案: