Question

目前，我正在列出一组数据，其中包含单独的＆＃34; UNION＆＃34; ed select语句，为每条信息创建一个新的行条目：

示例：

  (No column name)
1  40
2  11
3  13
4  29
5  64
6  34

我想要的是将其更改为带有标记列的行。

示例：

  Column 1   Column 2   Column 3   Column 4   Column 5   Column 6
1   40          11         13         29         64         34

我将如何做到这一点？

Answer 1

DECLARE @T TABLE (Val INT, SortOrder VARCHAR(20))
INSERT INTO @T
SELECT 40,'Column 1'
UNION
SELECT 11,'Column 2'
UNION
SELECT 13,'Column 3'
UNION
SELECT 29,'Column 4'
UNION
SELECT 64,'Column 5'
UNION
SELECT 34,'Column 6'

SELECT * FROM @T
pivot (avg (Val) for SortOrder in (
 [Column 1],[Column 2],[Column 3],[Column 4],[Column 5],[Column 6])
) as Whatever

rextester：http://rextester.com/LWZH64528

结果：

+----------+----------+----------+----------+----------+----------+
| Column 1 | Column 2 | Column 3 | Column 4 | Column 5 | Column 6 |
+----------+----------+----------+----------+----------+----------+
|       40 |       11 |       13 |       29 |       64 |       34 |
+----------+----------+----------+----------+----------+----------+

日期作为第一列值

DECLARE @T TABLE (Val VARCHAR(20), SortOrder VARCHAR(20))
INSERT INTO @T
SELECT '2016-10-12','Column 1'
UNION
SELECT '11','Column 2'
UNION
SELECT '13','Column 3'
UNION
SELECT '29','Column 4'
UNION
SELECT '64','Column 5'
UNION
SELECT '34','Column 6'

SELECT * FROM @T
pivot (MAX(Val) for SortOrder in ([Column 1],[Column 2],[Column 3],[Column 4],[Column 5],[Column 6])) as Whatever

结果：

+----------+----------+----------+----------+----------+----------+
| Column 1 | Column 2 | Column 3 | Column 4 | Column 5 | Column 6 |
+----------+----------+----------+----------+----------+----------+
|2016-10-12|       11 |       13 |       29 |       64 |       34 |
+----------+----------+----------+----------+----------+----------+

SQL Server联盟选择与不同＆＃39;其中＆＃39;单行的子句

1 个答案: