Question

我有一个如下文件 -

vipin kumar ........................ kumar ......bangalore
    something something .......
;
vipin kumar ........................ kumar ......bangalore
    something something .......(testing
)
;
vipin kumar ......................... kumar .....bangalore
something something ;

我想要输出如下（名称和数字在文件中可以不同但唯一的共同点 - 当我们有＆＃34 ;;＆＃34;）

vipin kumar ........................ kumar ......bangalore   something something .......;
vipin kumar ........................ kumar ......bangalore    something something .......(testing);
vipin kumar ......................... kumar .....bangaloresomething something ;

I want to set the RS to ";" .

我尝试了下面的命令 -

awk '{ORS=(NR%2==0?RS:FS)}1' file.txt

但是没有给出正确的输出，因为

NR%2 or NR%3无法工作，因为我不确定我将获得多少行;

然后我试图将RS设置为;使用下面的

awk '{for(i=1;i<=NF;i++) (ORS=(if($i ~ /;/?RS:FS);break}1' file.txt

但是这个命令不起作用。

Answer 1

<强>输入

$ cat f
vipin kumar ........................ kumar ......bangalore
    something something .......
;
vipin kumar ........................ kumar ......bangalore
    something something .......(testing
)
;
vipin kumar ......................... kumar .....bangalore
something something ;

<强>输出

$ awk 'ORS=/;/?RS:FS'  f
vipin kumar ........................ kumar ......bangalore     something something ....... ;
vipin kumar ........................ kumar ......bangalore     something something .......(testing ) ;
vipin kumar ......................... kumar .....bangalore something something ;

Answer 2

我得到了答案，但可能有其他方法可以做到这一点。

awk '{for(i=1;i<=NF;i++) (ORS=($i ~ /;/)?RS:FS)}1' file.txt
vipin kumar ........................ kumar ......bangalore     something something ....... ;
vipin kumar ........................ kumar ......bangalore     something something .......(testing ) ;
vipin kumar ......................... kumar .....bangalore something something ;

Answer 3

@VIPIN KUMAR：试试：

awk '/^vipin kumar/ && Q{print Q;Q=$0;next} {Q=Q?Q FS $0:$0} END{print Q}' Input_file

编辑：根据OP的要求，以下内容也有帮助。

awk '{printf("%s%s",$0,$0~/\;/?RS:"")}'  Input_file

Answer 4

我的第一个目的是使用它：

awk '{gsub(/\n/,"",$0); printf "%s;\n", $0}'  ORS='\n' RS=\; a.txt

...但我真的很喜欢Akshay Hegde's answer。

如何在awk中手动设置记录分隔符？

4 个答案: