我需要在路径为<th>A</th>
的表格中选择一个元素*[@id="something"]/table/thead/tr/th[2]
并更改其宽度。
(function ITPscript() {
$(document).ready(function() {
$("#something table thead tr:nth-child(2)").width(1000);
});
})();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="something" class="aaa">
<table class="sortable">
<thead>
<tr>
<th>0</th>
<th>A</th>
<th>B</th>
<th>C</th>
<th>D</th>
<th>E</th>
<th>F</th>
<th>G</th>
<th>H</th>
<th>I</th>
<th>J</th>
<th>K</th>
<th>L</th>
<th>M</th>
<th>N</th>
<th>O</th>
</tr>
</thead>
<tbody id="aBody">
<tr>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
</tr>
</tbody>
<tfoot></tfoot>
</table>
</div>
我正在使用$("#something table thead tr:nth-child(2)").width(140);
,但它不起作用。需要一种正确的方法来选择元素。
答案 0 :(得分:0)
:nth-child
未选择元素的第n个孩子,它会选择 的元素,即其父元素的第n个子元素。选择器必须是... tr th:nth-child(2)
:
(function ITPscript() {
$(document).ready(function() {
$("#something table thead tr th:nth-child(2)").width(1000);
});
})();
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="something" class="aaa">
<table class="sortable">
<thead>
<tr>
<th>0</th>
<th>A</th>
<th>B</th>
<th>C</th>
<th>D</th>
<th>E</th>
<th>F</th>
<th>G</th>
<th>H</th>
<th>I</th>
<th>J</th>
<th>K</th>
<th>L</th>
<th>M</th>
<th>N</th>
<th>O</th>
</tr>
</thead>
<tbody id="aBody">
<tr>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
</tr>
</tbody>
<tfoot></tfoot>
</table>
</div>