我的头脑是从(愚蠢)尝试使用JOIN
,WITH
和GROUP BY
吸烟为我常见的场景提出解决方案 - 我无法包裹我绕过它。让我立刻向你举出例子:
我有两张桌子(ColorCount和Colorname):
ColorCount:
ColorID Count Date
1 42 2010-09-07
1 1 2010-09-08
2 22 2010-09-14
1 20 2010-10-10
3 4 2010-10-14
ColorName:
ColorID Name
1 Purple
2 Green
3 Yellow
4 Red
现在我想要的是将ColorName表连接到ColorCount表,总结每月的所有颜色计数,并从每月总计算每个计数的百分比。表格比单词更好:
Output:
Month Color Count Percentage
09 Purple 43 66%
09 Green 22 33%
09 Yellow 0 0%
09 Red 0 0%
10 Purple 20 83%
10 Green 0 0%
10 Yellow 4 16%
10 Red 0 0%
(请注意,09
的总计数为65
,因此66%
的{{1}}以及Purple
的{{1}}不存在的颜色):
我希望有人在SQL中做梦,这是一件容易的事......
答案 0 :(得分:3)
这有效,但有以下警告:
代码:
;with cte (ColorId, Mth, TotalCount)
as (select
ColorId
,dateadd(dd, -datepart(dd, Date) + 1, Date) Mth
,sum(Count) TotalCount
from ColorCount
group by ColorId, dateadd(dd, -datepart(dd, Date) + 1, Date))
select
AllMonths.Mth [Month]
,cn.Name
,isnull(AggData.TotalCount, 0) [Count]
,isnull(100 * AggData.TotalCount / sum(AggData.TotalCount * 1.00) over (partition by AllMonths.Mth), 0) Percentage
from (select distinct Mth from cte) AllMonths
cross join ColorName cn
left outer join cte AggData
on AggData.ColorId = cn.ColorId
and AggData.Mth = AllMonths.Mth
order by AllMonths.Mth, cn.ColorId
答案 1 :(得分:2)
SELECT
[Month],
[Name],
[Count],
CASE WHEN TotalMonth=0 THEN 'INF' ELSE cast(round([Count],0)*100.0/TotalMonth,0) as int) + '%' END as [Percentage]
FROM
(
SELECT
[Months].[Month] as [Month],
CN.[Name],
isnull(CC.[Count],0) as [Count],
(SELECT SUM([Count]) FROM ColorCount WHERE
datepart(month,[Date])=datepart(month,CC.[Date])
) as [TotalMonth]
FROM (SELECT DISTINCT datepart(month,[Date]) as [Month] FROM ColorCount) [Months]
LEFT JOIN ColorName CN ON [Months].[Month]=datepart(month,CC.[Date])
LEFT JOIN ColorCount CC ON CN.ColorID=CC.ColorID
) AS tbl1
ORDER BY
[Month] ASC,
[Name] ASC
像这样...... 它不会显示当月的前导零,但它真的重要吗?