我正在尝试使用ArrayList对选择排序进行编码。我的程序要求我创建一个大小为20的数组,并用1到1000之间的随机整数填充它(没有用户输入或硬代码)。输出将要求显示原始未排序的整数列表,并在单独的行上显示排序算法的每个过程。
我尝试为选择排序创建一个方法,因此我不知道如何将代码实现到我的main方法中。
我希望输出如何显示的示例如下所示(尽管在我尝试做20时它只显示5个整数):
未排序列表:3 68 298 290 1
通过1:1 68 298 290 3
通过2:1 3 298 290 68
传球3:1 3 68 290 298
通过4:1 3 68 290 298
// Used to capture keyboard input
import java.util.*;
// Our class called SelectionSort
public class SelectionSort {
// Create doSelectionSort method
public static int[] doSelectionSort(int[] arr) {
for (int i = 0; i < arr.length - 1; i++) {
int pos = i;
// find position of smallest num between (i + 1)th element and last element
for (int j = i + 1; j <= arr.length; j++) {
if (arr[j] < arr[pos])
pos = j;
// Swap min (smallest num) to current position on array
int min = arr[pos];
arr[pos] = arr[i];
arr[i] = min;
}
}
return arr;
}
// Main method
public static void main(String[] args) {
ArrayList<Integer> array = new ArrayList<Integer>(); // Declare and instantiate a new ArrayList object
Scanner userChoice = new Scanner(System.in); // User input for quitting program
String choice = ""; // Will hold user choice to quit program
boolean inputFlag = false; // True if input is valid, false otherwise
// Repeat program until user chooses to quit
while (inputFlag = true) {
System.out.print("\nWould you like to continue the program? (Y/N): ");
choice = userChoice.nextLine();
if (choice.equalsIgnoreCase("Y")) {
try {
/* Create an array of size 20 and populate it with random integers between 1 and 1000.
Do not ask user for the numbers and do not hard code them */
for (int i = 0; i < 20; i++) {
int integer = (int)(1000.0 * Math.random());
array.add(integer);
}
System.out.print("\nUNSORTED LIST: ");
//Display the 20 size of the unsorted ArrayList
for (int i = 0; i < array.size() - 1; i++) {
System.out.print(array.get(i) + ", ");
}
// Shows very last integer with a period
System.out.print(array.get(array.size() - 1) + ".");
System.out.println();
}
catch (IndexOutOfBoundsException e) {
System.out.println("\nThere is an out of bounds error in the ArrayList.");
}
// Display each pass of the sorting algorithm on a separate line
for (int i = 1; i < array.size(); i++) {
System.out.print("PASS " + i + ": ");
for (int arr2:array) {
System.out.print(arr2 + ", ");
}
System.out.print(array.get(array.size() - 1) + ".\n");
}
array.clear();
}
else if (choice.equalsIgnoreCase("N")) {
break;
}
// Error message when inputting anything other than Y/N
else {
System.out.println("\nERROR. Only Y, y, N, or n may be inputted.");
System.out.println("Please try again.");
}
}
}
}
我也无法从每次传球中移除最后一个号码,因为它被显示两次..知道我应该做什么吗?
很抱歉我的编码没有任何意义,我仍然试图理解它。
答案 0 :(得分:3)
我修复了你的代码,现在应该可以了。
<child1 #child1></child1>
<child2 (someOutput)="child1.doSomething($event)"></child2>
答案 1 :(得分:0)
你的方法doSelectionSort似乎没问题,但它完成整个排序。如果要显示每次迭代,只需添加一行:
public static int[] doSelectionSort(int[] arr) {
for (int i = 0; i < arr.length - 1; i++) {
int pos = i;
// find position of smallest num between (i + 1)th element and last element
for (int j = i + 1; j <= arr.length; j++) {
if (arr[j] < arr[pos])
pos = j;
// Swap min (smallest num) to current position on array
int min = arr[pos];
arr[pos] = arr[i];
arr[i] = min;
}
System.out.println("Pass "+pos+" : "+arr);
}
return arr;
}