Question

我需要你的帮助，因为我的SQL级别非常弱，我正在尝试做某些事情但却找不到如何实现它。

假设我有以下行

| Data| Status |   Date     |
| A   |  OK    | 2017-01-20 |
| B   |  KO    | 2017-01-20 |
| C   |  OK    | 2017-01-20 |
| A   |  OK    | 2017-01-21 |
| B   |  KO    | 2017-01-21 |
| C   |  KO    | 2017-01-21 |
| A   |  OK    | 2017-01-22 |
| B   |  KO    | 2017-01-22 |
| C   |  OK    | 2017-01-22 |

我想查询数据库以获得OK的百分比结果3天，所以它看起来像

A | 100%
B | 0%
C | 66%

我为1个数据做过这个，但是我被卡住了，也许我需要一个循环或其他东西：

Select 
    Data, (Select Count(*) From DB Where 
    Date between '2017-01-20' and '2017-01-22' 
    And Status = 'OK') * 100 / (Select Count(*) From DB 
                                Where Date between '2017-01-20' and '2017-01-22')

From 
    DB

Answer 1

试试这个：

SELECT Data, CAST(CAST(AVG((CASE WHEN Status='OK' THEN 100.0 ELSE 0.0 END)) AS INT) AS VARCHAR(MAX)) + '%'
FROM DB
WHERE Date BETWEEN '2017-01-20' AND '2017-01-22'
GROUP BY Data

Try it in Data Explorer *特别感谢@ t-clausen.dk将这个令人敬畏的工具引入我的注意

Answer 2

SELECT
  100*(count(*)-count(nullif(Status,'OK')))/count(*), Data
FROM 
  <yourtable>
WHERE
  Date between'2017-01-20' and '2017-01-22' 
GROUP BY
  Data

<强> Try it out

Answer 3

试试这个：

Pay: <select id="pay">
<option value="">Please select</option>
<option value="0">Zero</option>
<option value="1">One</option>
</select>
<input type="text" id="callback" />: <span id="result"></span>

OR

select m.data, ISNULL(((max(tot)*100)/count(m.status)), 0) percentage
from myTable m
LEFT JOIN (select data, count(status) tot from myTable m1 where status ='ok' and date between '2017-01-20' and '2017-01-22' group by m1.data) m2 on m2.data = m.data
where date between '2017-01-20' and '2017-01-22'
group by m.data

Answer 4

<强>查询

select [Data],
((cast((sum(case [Status] when 'OK' then 1 else 0 end)) as decimal(5, 2))) / 
cast(count([Data]) as decimal(5, 2))) * 100.00 as perc
from [your_table_name]
where [Date] between '2017-01-20' and '2017-01-22'
group by [Data];

SQL Server：计算百分比

4 个答案: