Question

我正在尝试在showName div中显示更新后的值，但我的网站仅在注销并再次登录后显示更新后的值。

按saveName按钮更新用户名。
在PHPMyAdmin users表中成功更新用户名。
showName div仍显示旧用户名。即使我刷新页面。

的index.php

<div id="showName">
<?php
    if(isset($_SESSION['userId'])){
        echo $_SESSION['username']; }
?>
</div>
<div id="message"></div>
<div> <input id="editName" name="editName" /> </div>

<button id="saveName" type="submit" >Save</button>

edit.php

<?php
ob_start();
session_start();

include_once('database.php');

$validUser= $_SESSION["username"];

if(isset($_POST['editName']))
{   
    $username = $_POST["editName"];

    if ($username =="") {
        echo "Enter your full name.";
        return false;
    }else {
        $sql = "UPDATE users SET username='$username' WHERE username='$validUser'";

        if(mysqli_query($con, $sql)){
            echo "Successfully Updated.";
        } else{
            echo "Something went wrong"; }
    }
    return false;
}
    ob_end_flush(); 
?>

的script.php

$("#saveName").click( function(e) {
    e.preventDefault();
    e.stopPropagation();

    $.post("edit.php",
    $("#editName").serializeArray(),
         function(info){ $("#message").html(info);
    });

});

Answer 1

在数据库中更新后，您必须将新用户名置于会话中。 $_SESSION["username"] = $your_new_username

<? php
ob_start();
session_start();

include_once('database.php');

$validUser = $_SESSION["username"];

if (isset($_POST['editName'])) {
  $username = $_POST["editName"];

  if ($username == "") {
    echo "Enter your full name.";
    return false;
  } else {
    $sql = "UPDATE users SET username='$username' WHERE username='$validUser'";

    if (mysqli_query($con, $sql)) {
      echo "Successfully Updated.";
      $_SESSION["username"] = $username // Updating the new username to session
    } else {
      echo "Something went wrong";
    }
  }
  return false;
}
ob_end_flush(); ?>

PHP无法显示更新的值

1 个答案: