Question

我只是python的初学者。我在这里写了一个简单的程序，只是为了自我评估自己，并尝试以随机顺序回答问题。但这里的错误是randint函数有时会获得相同的数字我已经获得了相同的问题。我尽力解决它，但我不能。希望我能在这里得到一些帮助。随机进口

function destroyer(arr, param2, param3) {
  // Remove all the values
  console.log("---");
  console.log("arr: " + arr);
  var args = Array.from(arr);
  console.log(args);
  var in_i = arr[0];

  return in_i.filter(function (x) {
    if (args.indexOf(x) !== -1) {
      return true;
    } else {
      return false;
    }
  });
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

Answer 1

在你的函数之前，添加一组布尔值来描述哪些问题已被回答：

already_asked = [False] * len(names)

然后，在你将qno分配给一个值的地方，继续生成随机数，直到你找到之前没有问过的那个，然后按照要求标记新问题：

qno = random.randint(0, len(names))
while already_asked[qno]:
    qno = random.randint(0, len(names))
already_asked[qno] = True

Answer 2

random.shuffle功能完全符合您的要求。

Answer 3

如果你使用randomint（0,14），你必须得到很多重复！例如：

import random

names=['electric charge','permitivity of the medium','permitiovity of free space','relative permitivity of the medium','intensity  of the electric field','electric potential at a point','electric potential energy','dipole moment','torque acting on the dipole','electric flux','linear charge density of the conductor','surface charge density of the conductor','capacitance of a parallel plate capacitor','practical unit of capacitance']


for i in range(10):
...     print( random.randint(0,len(names)))

这是我第一次运行时的输出：

注意我是如何获得数字6三次的！显然重复会随着范围的增加而减少，但是你总是有机会重复数字，特别是因为这只是伪随机生成的数字。

也许你正在寻找像洗牌这样的东西？例如：

>>> new_order = ([ i for i in range(len(names)) ])
>>> random.shuffle(new_order)
>>> print(new_order)
[9, 10, 7, 8, 4, 13, 0, 2, 3, 6, 12, 5, 1, 11]

Answer 4

可能有点高级，很高兴有不需要显式索引的选项

import random

names=['electric charge','permitivity of the medium','permitiovity of free space','relative permitivity of the medium','intensity  of the electric field','electric potential at a point','electric potential energy','dipole moment','torque acting on the dipole','electric flux','linear charge density of the conductor','surface charge density of the conductor','capacitance of a parallel plate capacitor','practical unit of capacitance']
answer=['C','C2N-1m-2','C2N-1m-2','no unit','NC-1 or Vm-1','V','J','Cm','Nm','Nm2C-1','Cm-1','Cm-2','F','uF or pF']

# zip, list comprehensions are useful things to learn
# this helps keep things together without explicit index calcs
name_answer_pairs = [(n, a) for n, a in zip(names, answer)]

atest = name_answer_pairs[:] # need a copy, atest gets modified below
random.shuffle(atest)

yes = False

while atest:     # loops until atest is empty, add your UI code to loop
    quest, ansr = atest.pop()   # gets the pair, removes the tuple from the end
    print('Q: ',quest, '\n', 'Ans: ', ansr) # just to show an example

    # do your user Q/A thing here

    # check if atest is empty, to repeat loop with new atest, refresh atest:
    if not atest:
    # ask user to continue?, set 'yes' True or False
        if yes:    
            atest = name_answer_pairs[:]    
            random.shuffle(atest)           # new atest, different order
            continue
        else:
            break

Q:  practical unit of capacitance 
 Ans:  uF or pF
Q:  electric charge 
 Ans:  C
Q:  capacitance of a parallel plate capacitor 
 Ans:  F
Q:  dipole moment 
 Ans:  Cm
Q:  intensity  of the electric field 
 Ans:  NC-1 or Vm-1
Q:  electric potential energy 
 Ans:  J
Q:  permitiovity of free space 
 Ans:  C2N-1m-2
Q:  electric flux 
 Ans:  Nm2C-1
Q:  permitivity of the medium 
 Ans:  C2N-1m-2
Q:  torque acting on the dipole 
 Ans:  Nm
Q:  relative permitivity of the medium 
 Ans:  no unit
Q:  surface charge density of the conductor 
 Ans:  Cm-2
Q:  electric potential at a point 
 Ans:  V
Q:  linear charge density of the conductor 
 Ans:  Cm-1

现在我在{+ 1}}添加了while True:在循环结束

，

可能是if not atest

Python-randint函数没有重复

4 个答案: