使用连接

Question

我的mysql架构如下所示：

+---------+---------+----------+ +---------+-----------+
| user_id | club_id | username | | club_id | club_name |
+---------+---------+----------+ +---------+-----------+
| 1       | 1       | bob      | | 1       | bobcats   |
| 2       | 1       | tom      | | 2       | carguys   |
| 3       | 1       | sam      | +---------+-----------+
| 4       | 2       | mat      |
+---------+---------+----------+

我想要一个返回的选择查询：

+---------+-----------+-------------+
| club_id | club_name | num_members |
+---------+-----------+-------------+
| 1       | bobcats   | 3           |
| 2       | carguys   | 1           |
+---------+-----------+-------------+

我试过了：

SELECT clubs.club_id
     , clubs.club_name
     , COUNT(DISTINCT users.club_id) AS num_members 
  FROM users 
  JOIN clubs 
    on users.club_id = clubs.club_id 
 ORDER 
    BY clubs.club_name

当我尝试时（仅第一排而不是所有球杆）我得到了什么：

+---------+-----------+-------------+
| club_id | club_name | num_members |
+---------+-----------+-------------+
| 1       | bobcats   | 3           |
+---------+-----------+-------------+