Question

我的声明正在发挥作用：

import java.util.*;
public class Recursion{

public static int sumOfInt(int x)
{           
  int sum =0;
  if (x <= 1)
     return x;

  else
     sum += x % 10; 
  x /= 10; 
  return sum + sumOfInt(x);
}

public static void main (String [ ] arg){


  Scanner sc = new Scanner(System.in);
  int userInt = 0;
  boolean userInput = false;
  boolean endLoop = false;
  String userAgain = "";


 do{
  do{
     try{
        System.out.print("Please enter an integer number: ");
        userInt = sc.nextInt();
        userInput = true;


     }
     catch(InputMismatchException ime) {
        System.out.println("You did not enter an integer number");
        sc.nextLine(); 
     }

   }while(userInput == false);

   System.out.println("The integer you entered is " + userInt);
   System.out.println("The sum of the digits in the integer you entered is " + sumOfInt(userInt));
        System.out.println();
        System.out.println("Enter yes to try again");

        userAgain = sc.nextLine();
        // I don't understand why the above line is not waiting for a user response before quitting.

         if(userAgain == "yes"){
           endLoop = false;
         }else{
           endLoop = true;
         }



   }while(endLoop == false);

 }
 }

我试图做这样的事情，但它不起作用：

CASE [Level 1]
WHEN '2017' THEN ''
WHEN '2016' THEN '' 
WHEN '2015' THEN ''
WHEN '2014' THEN ''
ELSE [Level 1]
END

关于如何使第二个陈述有效的建议？

Answer 1

你想要这样的东西：

  CASE WHEN [LEVEL 1] LIKE 'CALENDAR MONTH%' THEN 'CALENDAR MONTH'
       WHEN [LEVEL 1] LIKE 'CALENDAR WEEK%' THEN 'CALENDAR WEEK'
       WHEN [LEVEL 1] LIKE 'CALENDAR QUARTER%' THEN 'CALENDAR QUARTER'
       ELSE [LEVEL 1]
  END

情况何时有多个

1 个答案: