Question

我试图用angular2来概括制作Telerik Grid。在我的组件中我有：

# your existing code
dwg = ezdxf.readfile('path_to_my_file.dxf')
for layer in dwg.layers:
    if layer.dxf.name == 'old_layer_name':
        layer.dxf.name == 'new_layer_name'

# this is the part that's untested
for entity in dwg.entities:
    if entity.layer.dxf.name == 'old_layer_name':
        entity.layer.dxf.name == 'new_layer_name'

正确获取数据（我试过没有案例并且工作正常）然后在我的模板html：

 private cols: Column[] = [
    { name: 'id', desc: 'ID' },
    { name: 'listen', desc: 'Listen' },
    { name: 'station', desc: 'Station' },
    { name: 'location', desc: 'Location' },
    { name: 'type', desc: 'Type' },

];

我想为每列应用不同的处理。在ngFor模板之后如何在这种情况下应用ngSwitch。我试过几种方式，比如添加<kendo-grid [data]="gridPager"> <template *ngFor="let col of cols" let-col> </template> </kendo-grid>或

<span [ngSwitch]="col.name", {{"col.name"}}

但无济于事。

Answer 1

我终于找到了方法，并为其他人发帖。

<template ngFor [ngForOf]="cols" let-col>
        <kendo-grid-column field="{{col.name}}" title="{{col.desc}}" [ngSwitch]="col.name" [sortable]="col.name!='listen'">
            <template kendoGridCellTemplate let-dataItem let-column *ngSwitchCase="'listen'">
                <button kendoButton (click)="open(dataItem) " style="width:180">{{dataItem.station.text}}</button>
            </template>
            <template kendoGridCellTemplate let-dataItem let-column *ngSwitchCase="'station'">
                <a href="{{dataItem.station.href}}" target="_new">{{dataItem.station.text}}</a>
            </template>
        </kendo-grid-column>
    </template>

Telerik angular2网格模板开关

1 个答案: