Question

我正在尝试在2个表episodes和filters之间使用HABTM关联。关联表为episodes_filters。我想找到所有匹配过滤器ID 1和2的剧集。我的理解是CakePHP默认情况下会执行AND条件，但我的努力导致返回的结果与剧集ID 1或2匹配，或者根本没有结果。< / p>

以下是我到目前为止使用代码登陆的地方：

$filterConditions = array();
foreach($filterIds as $filterId ) {
    $filterConditions[] = array('EpisodesFilters.filter_id' => $filterId);
}

$episodeFilters = $this->Episode->find('all', array(
    'conditions' => array(
        'Episode.organization_id' => $this->Auth->user('organization_id'),
        'Episode.status' => $this->request->query['episode_status']
    ),
    'joins' => array(
        array('table' => 'episodes_filters',
            'alias' => 'EpisodesFilters',
            'type' => 'INNER',
            'conditions' => array(
                $filterConditions,
                'EpisodesFilters.episode_id = Episode.id'
            )
        )
    ),

));

我尝试将每个过滤器ID设置为JOIN它自己的状态，而不是像以下数组那样：＆＃39; EpisodesFilters.filter_id＆＃39; =＆GT;数组（1,2），但这会导致使用过滤器1或2返回剧集，而不是两者。

有人可以帮我确定如何为HABTM查找设置这个条件吗？

Answer 1

foreach($filterIds as $filterId ) {
    $filterConditions['and']['EpisodesFilters.filter_id'][] = $filterId;
}

没有循环的OR

$filterConditions['and']['EpisodesFilters.filter_id'] = $filterIds;

Answer 2

首先制作AND条件数组，从$filterIds var：

分别为每个AND条件创建一个新数组

foreach( $filterIds as $filter_id ) {
    $filterConditions['AND'][] = array('EpidodesFilters.filter_id' => $filter_id);
}

然后你的find命令中的条件项将是：

'conditions' => array(
    'AND' => $filterConditions
)

Cakephp 2 HABTM找到AND条件

2 个答案: