有人可以建议如何从IndexedDB objectstore获取多个键值吗?我做了多个选项,但没有做任何事。 在这里创建了indexedDb
$provide.value('dbModel', {
name: 'TestDB',
version: '1',
instance: {},
objectStoreName: {
dashboards: 'Appointment'
},
upgrade: function (e) {
var db = e.target.result;
if (!db.objectStoreNames.contains('Appointment')) {
var calendarobj = db.createObjectStore('Appointment', {
keyPath: 'AppointmentId'
});
calendarobj.createIndex("AppointmentId", "AppointmentId", { multiEntry: true });
}
}
});
数据看起来像
KeyPath-AppointmentId Value
===================== =====
1 Test 1
2 Test 2
3 Test 3
我有getObjectStore方法来获取objectstorename实例。
getObjectStore: function (objectStoreName, mode) {
var modeact = mode || _db.transactionTypes.readonly;
var txn = _db.instance.transaction(objectStoreName, modeact);
var store = txn.objectStore(objectStoreName);
return store;
}
var keys = [1,2]; // Want to get the First two record which has value 'Test 1' and 'Test 2'
var store = _db.getObjectStore(objectStoreName);
var tagIndex = store.index(store.keyPath); //AppointmentId
var request = tagIndex.openCursor(IDBKeyRange.only(keys));
//var request = tagIndex.get(keys);
request.onsuccess = function (event) {
console.log(event.result);
}
答案 0 :(得分:3)
使用[1, 2]
,因为您确实无法工作 - 这是一个恰好是有两个成员的数组的密钥。索引数据库目前不了解使用列表或密钥集进行查询。
您有一些选择:
1 - 并行发出两个get请求。 (由于订单有保证,第二个请求将在第一个请求之后完成,您知道两个结果都将被返回。)
var results = [];
store.get(1).onsuccess = function(e) {
results.push(e.target.result);
};
store.get(2).onsuccess = function(e) {
results.push(e.target.result);
// results will have the values
};
2 - 使用光标和范围:
var results = [];
store.openCursor(IDBKeyRange.bound(1, 2)).onsuccess = function(e) {
var cursor = e.target.result;
if (cursor) {
results.push(cursor.value);
cursor.continue();
} else {
// results will have the values
}
};
3 - 将getAll与范围一起使用(仅限较新的浏览器 - 如果不可用,则返回光标)
store.getAll(IDBKeyRange.bound(1, 2)).onsuccess = function(e) {
// e.target.result will have the entries
};
请注意,在使用范围的选项2和3中,如果存在密钥,您还会获得密钥为1.5
的记录。
答案 1 :(得分:2)
这可以与Multiple keys query in IndexedDB (Similar to OR in sql)复制,但是我无权报告重复,因此我将再次发布答案。希望对您有所帮助。
// [store]: object store
// [keys]: array of keys
// return: An object of key-value pairs
const get = (store, keys) =>
Promise.all(
keys.map(
(key) =>
new Promise((resolve, reject) => {
const request = store.get(key);
request.onsuccess = ({ target: { result } }) => resolve(result);
request.onerror = ({ target: { error } }) => reject(error);
})
)
).then((values) =>
keys.reduce(
(result, key, index) => ((result[key] = values[index]), result),
{}
)
);
const request = indexedDB.open("test");
request.onupgradeneeded = ({ target: { result: db } }) => {
db.createObjectStore("settings").transaction.oncomplete = ({
target: { db },
}) => {
const store = db
.transaction("settings", "readwrite")
.objectStore("settings");
store.add(123, "foo");
store.add(456, "bar");
};
};
request.onsuccess = ({ target: { result: db } }) => {
get(db.transaction("settings").objectStore("settings"), [
"foo",
"bar",
"buz",
]).then(console.log); // {foo: 123, bar: 456, buz: undefined}
};