Question

我尝试按照how to implement nested item in scrapy?中的建议嵌套项目但是我收到以下错误消息：

i[a]

我该怎么迭代？我已经尝试将以下内容插入到Sons.Item类中：

Traceback (most recent call last):


File "/home/x/workspace/Crawler/venv/local/lib/python2.7/site-packages/scrapy/utils/defer.py", line 102, in iter_errback
    yield next(it)
  File "/home/x/workspace/Crawler/venv/local/lib/python2.7/site-packages/scrapy/spidermiddlewares/offsite.py", line 29, in process_spider_output
    for x in result:
  File "/home/x/workspace/Crawler/venv/local/lib/python2.7/site-packages/scrapy/spidermiddlewares/referer.py", line 22, in <genexpr>
    return (_set_referer(r) for r in result or ())
  File "/home/x/workspace/Crawler/venv/local/lib/python2.7/site-packages/scrapy/spidermiddlewares/urllength.py", line 37, in <genexpr>
    return (r for r in result or () if _filter(r))
  File "/home/x/workspace/Crawler/venv/local/lib/python2.7/site-packages/scrapy/spidermiddlewares/depth.py", line 58, in <genexpr>
    return (r for r in result or () if _filter(r))
  File "/home/x/workspace/Crawler/test.py", line 53, in parse
    s1['grandsons'] = [dict(gs1), dict(gs2)]
TypeError: iteration over non-sequence

但它没有帮助。我在这做错了什么？谢谢。：）

完整的代码是：

def __iter__(self):
    return iter(self.grandsons)

scrapy json嵌套项目

0 个答案: