我正在调用该函数,而a
并未保留以下函数中的值mob_f
return
:
a = get_mobile()
功能是:
def get_mobile():
ws = sheet_select()
mobile = []
mob_i = []
mob_f = []
mob_j = []
for col in ws.iter_cols():
for cell in col:
if cell.value == 'Mobile':
x=column_index_from_string(cell.column)
for row in ws.iter_rows(min_col = x, min_row = 2, max_col = x):
for cell in row:
if cell.value != None:
mobile.append(cell.value)
for i in mobile:
h = i
h = h.replace(" ", "")
h = h.replace("+(91)-", ",")
h = h.replace("+91", "")
h = h.replace("-", "")
mob_i.append(h)
for i in mob_i:
h = i
h = h.split(',')
mob_j.append(h)
mob_x = [item for sublist in mob_j for item in sublist]
for i in mob_x:
if i != '':
h = i
return mob_f.append(h)
如果我使用代码时没有将其定义为function
,那么它运行没有问题,我得到mob_f
。
我认为问题是return
放错了。我尝试了很多组合并且一直都在失败。也是昨晚同样的功能正在运作,我无法理解我哪里出错了。
答案 0 :(得分:1)
Append什么都不返回,我想你想要这个:
...
for i in mob_x:
if i != '':
h = i
mob_f.append(h)
return mob_f