Question

我有这段代码

<?php if($grades->subcompid==$subcomp->id && $grades->compid=='1' && $grades->termid=='1' && $grades->recordid==$recid && $grades->studentid==$student->studentid){
   echo $grades->grade;
?>

我希望回显值20,25,14,12和45--上面的代码是这样做的。

问题是我想添加这些值以获得116所以我这样做了：

$midtermg = 0;    
<?php if($grades->subcompid==$subcomp->id && $grades->compid=='1' && $grades->termid=='1' && $grades->recordid==$recid && $grades->studentid==$student->studentid){
    $midtermg = $midtermg + $grades->grade;
    echo $midtermg;
}

然而它返回值'20 45 59 71 116'。它将值添加到下一个值并回显每个值。我尝试了echo end($midtermg);，但它说它不是一个数组，所以它不起作用。如果我只想让116回应怎么办？

* if语句返回正确的值，所以请不要介意

Answer 1

喜欢这样。每次在if内打印价值。只需在循环内汇总值。并在if条件后打印。

<?php
$midtermg = 0;    
 if($grades->subcompid==$subcomp->id && $grades->compid=='1' && $grades->termid=='1' && $grades->recordid==$recid && $grades->studentid==$student->studentid){
    $midtermg = $midtermg + $grades->grade;

} 

echo $midtermg;

Answer 2

初始化一个数组并将条件满足值推入数组，然后你可以使用这个数组。

<?php
$midtermg = 0;
$a_results= array();    
if($grades->subcompid==$subcomp->id && $grades->compid=='1' && $grades->termid=='1' && $grades->recordid==$recid && $grades->studentid==$student->studentid){
    // $midtermg = $midtermg + $grades->grade;
    array_push($a_results, $grades->grade);
} 
echo array_sum($a_results);

添加在foreach php中返回的值

2 个答案: