我需要迭代并从JSON响应中获取最后一个值,如name,url和color。使用java / gson api。请帮帮我。
{
"Title": {
"desc": [
{
"name": "PRE_DB",
"url": "http://jenkins.example.com/job/my_first_job/",
"color": "blue_anime"
},
{
"name": "SDD_Seller_Dashboard",
"url": "http://jenkins.example.com/job/my_second_job/",
"color": "blue_anime"
}
]
}
}
示例输出: 名称:SDD_Seller_Dashboard 颜色:blue_anime
答案 0 :(得分:1)
JSONObject data = new JSONObject(your_JSON_Repsonse);
JSONArray data_desc=data.getJSONArray(desc);
for(int i=0;i<=data_desc.length();i++)
{
name=data_desc.getString("name");
url=data_desc.getString("url");
color=data_desc.getString("color");
}