Question

我为扫雷问题编写了一个代码。它创建了一个MxN扫雷游戏，其中每个细胞都是概率为p的炸弹。打印m-by-n游戏和邻近的炸弹计数。 Code:

class Minesweeper { 
    public static void main(String[] args) { 
        int m = Integer.parseInt(args[0]);
        int n = Integer.parseInt(args[1]);
        double p = Double.parseDouble(args[2]);

    try {
        boolean[][] bombs = new boolean[m+2][n+2];
        for (int i = 1; i <= m; i++)
            for (int j = 1; j <= n; j++)
                bombs[i][j] = (Math.random() < p);


        for (int i = 1; i <= m; i++) {
            for (int j = 1; j <= n; j++)
                if (bombs[i][j]) System.out.print("* ");
                else             System.out.print(". ");
            System.out.println();
        }


        int[][] sol = new int[m+2][n+2];
        for (int i = 1; i <= m; i++)
            for (int j = 1; j <= n; j++)
                // (ii, jj) indexes neighboring cells
                for (int ii = i - 1; ii <= i + 1; ii++)
                    for (int jj = j - 1; jj <= j + 1; jj++)
                        if (bombs[ii][jj]) sol[i][j]++;


        System.out.println();
        for (int i = 1; i <= m; i++) {
            for (int j = 1; j <= n; j++) {
                if (bombs[i][j]) System.out.print("* ");
                else             System.out.print(sol[i][j] + " ");
            }
            System.out.println();
        }
    }
    catch (Exception e) {
        e.printStackTrace();
    }

    }
}

解析后我需要提供任何条件吗？

int m = Integer.parseInt(args[0]);
int n = Integer.parseInt(args[1]);
double p = Double.parseDouble(args[2]);

请帮帮我。

Answer 1

在解析参数之前给出一个额外的条件。

if (args.length >= 3) {
    m = Integer.parseInt(args[0]);
    n = Integer.parseInt(args[1]);
    p = Double.parseDouble(args[2]);
}

线程＆＃34; main＆＃34;中的例外情况java.lang.ArrayIndexOutOfBoundsException：0错误

1 个答案: