Question

我使用以下javascript来查看业务是否根据营业时间打开。它很简单，效果很好，但是如何在凌晨0:30或凌晨1点的午夜时分完成这项工作。不幸的是，它仅适用于17：00-23：00但不适用于17：00-030：

var d = new Date();
var n = d.getDay();
var now = d.getHours() + "." + d.getMinutes();
var weekdays = [
    ["Sunday", 9.30, 12.00, 15.30,22.00],
    ["Monday", 8.30, 12.00, 15.30,19.00],
    ["Tuesday", 8.30, 12.00, 15.30,19.00],
    ["Wednesday", 8.30, 12.00, 15.30,19.00],
    ["Thursday", 8.30, 12.00, 15.30,19.00],
    ["Friday", 8.30, 11.30],
    ["Saturday"] // we are closed, sorry!
];
var day = weekdays[n];


if (now > day[1] && now < day[2] || now > day[3] && now < day[4]) {
    console.log("We're open right now!");
}
 else {
    console.log("Sorry, we're closed!");
}

我知道这个脚本不支持时区，但这对我来说并不重要，因为这只适用于与客户永远处于同一时区的本地商家。

提前谢谢。 PS：原始脚本来自stackoverflow Javascript Store Opening Hours

中的另一篇帖子

更新版本我更改了脚本，因为我使用了来自firebase的json数据并且已经获得了当天的时间，所以我不需要带有日期的数组。

<script>

    var d = new Date();
    var n = d.getDay();
    var now = d.getHours() + "." + d.getMinutes();

    // this is what I get from firebase already 
    // so I dont need to loop throught the days but throught the 2 different opening times.
    var day = {
    "from": 8.30,
    "to": 10,
    "from2": 14.30,
    "to2": 23    
    };

console.log('Now: ' + now);

    if (now > day.from && now < day.to || now > day.from2 && now < day.to2) {
        console.log("We're open right now!");
    } else {
        console.log("Sorry, we're closed!");
    }

</script>

如果我有17：00-01：00之类的东西，这怎么可能不起作用。

Answer 1

您可以使用本地时间或使用日期库，例如http://www.datejs.com/或https://momentjs.com/

解析(new Date).toLocaleString()并根据此日期时间处理您的数据。

var date = new Date();
var formatted = date.toLocaleString('de-DE');

要获取时区，您可以使用navigator.language

Answer 2

你可以尝试这样的事情。

var d = new Date();
var n = d.getDay();
var now = d.getHours() + "." + d.getMinutes();
var weekdays = [
    ["Sunday", 9.30, 12.00, 15.30,2.00],
    ["Monday", 8.00, 12.00, 15.30,19.00],
    ["Tuesday", 8.30, 12.00, 15.30,19.00],
    ["Wednesday", 8.30, 12.00, 15.30,19.00],
    ["Thursday", 8.30, 12.00, 15.30,19.00],
    ["Friday", 8.30, 11.30],
    ["Saturday"] // we are closed, sorry!
];
var day = weekdays[n];


if (now < day[1] && now > day[2] || now < day[3] && now > day[4]) {
      console.log("Sorry, we're closed!");
}
 else {
   if(n != 0){
     day = weekdays[n-1];
   }
   else{
     day = 6;
   }

   if ((now > day[4])) {
     console.log("Sorry, we're closed!");
  }
   else {
     console.log("We're open right now!");
  }
}

Answer 3

经过测试后，我自己找到了一条路。我最终创建了一个小功能。您可以将打开和关闭时间发送给该功能，并在业务开放或关闭时获得回复。适用于所有时间，也适用于午夜。

但是，此脚本不适用于其他时区的业务，因为它不会考虑任何基于位置的时间。如果您使用本地业务，客户在同一时区，因此业务正常。

   // Example with JSON data for the current day.
    var day = {
    "from": 17.30,
    "to": 1.30
    };

var check_now = check_business_status(day.from, day.to);
console.log('The bussines is ' + check_now);

function check_business_status(from, to) {

    var d = new Date();
    var n = d.getDay();
    var now = d.getHours() + "." + d.getMinutes();

console.log('Now: ' + now);
console.log(from + ' // ' + to);

// First check if to date is smaller than from date and their for tomorrow!
if (from > to){
console.info('Closing time is after midnight! Special Check...');

    var status = '';
    if (now < to && from > now) {
        status = "open";
    } else if (now > to && from > now) {
        status = "closed";
    } else if (now > to && from < now && now > from) {
       status = "open";
    }

} else {
console.info('Closing time is before midnight! Normal Check...');
    if (now > from && now < to) {
        status = "open";
    } else {
        status = "closed";
    }
}
 return status;
}

您还可以在jsfiddle https://jsfiddle.net/oliver2000/4pdogett/1/

中的不同时间进行测试

如何让这个javascript与午夜营业时间一起工作？

3 个答案: