Question

我是Tensorflow的新手，并想知道是否可以使用Tensorflow最小化一个变量的函数。

例如，我们可以使用Tensorflow使用初始猜测（比如x = 1）来最小化2 * x ^ 2 - 5 ^ x + 4吗？

我正在尝试以下方法：

import tensorflow as tf
import numpy as np

X = tf.placeholder(tf.float32, shape = ())
xvar = tf.Variable(np.random.randn())    
f = 2*mul(X,X) - 5*X + 4

opt = tf.train.GradientDescentOptimizer(0.5).minimize(f)

with tf.Session() as sess:
    tf.global_variables_initializer().run()
    y = sess.run(opt, feed_dict = {X : 5.0}) #initial guess = 5.0
    print(y)

但这会产生以下错误：

ValueError: No gradients provided for any variable, check your graph for ops that do not support gradients, between variables

请帮助我理解我在这里做错了什么。

Answer 1

如果您想最小化单个参数，您可以执行以下操作（我已经避免使用占位符，因为您正在尝试训练参数 - 占位符通常用于超参数和输入，并且不是＆＃39;被认为是可训练的参数）：

import tensorflow as tf

x = tf.Variable(10.0, trainable=True)
f_x = 2 * x* x - 5 *x + 4

loss = f_x
opt = tf.train.GradientDescentOptimizer(0.1).minimize(f_x)

with tf.Session() as sess:
    sess.run(tf.global_variables_initializer())
    for i in range(100):
        print(sess.run([x,loss]))
        sess.run(opt)

这将输出以下对（f，loss）列表：

[10.0, 154.0]
[6.5, 56.0]
[4.4000001, 20.720001]
[3.1400001, 8.0192013]
[2.3840001, 3.4469128]
[1.9304, 1.8008881]
[1.65824, 1.2083197]
[1.494944, 0.99499512]
[1.3969663, 0.91819811]
[1.3381798, 0.89055157]
[1.3029079, 0.88059855]
[1.2817447, 0.87701511]
[1.2690468, 0.87572551]
[1.2614281, 0.87526155]
[1.2568569, 0.87509394]
[1.2541142, 0.87503386]
[1.2524685, 0.87501216]
[1.2514811, 0.87500429]
[1.2508886, 0.87500143]
[1.2505331, 0.87500048]
[1.2503198, 0.875]
[1.2501919, 0.87500024]
[1.2501152, 0.87499976]
[1.2500691, 0.875]
[1.2500415, 0.875]
[1.2500249, 0.87500024]
[1.2500149, 0.87500024]
[1.2500089, 0.875]
[1.2500054, 0.87500024]
[1.2500032, 0.875]
[1.2500019, 0.875]
[1.2500012, 0.87500024]
[1.2500007, 0.87499976]
[1.2500005, 0.875]
[1.2500002, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]
[1.2500001, 0.87500024]

Answer 2

这是使用tensorflow 2.0具有相同输出的相同解决方案

import tensorflow as tf
from tensorflow.python.training import gradient_descent

x = tf.Variable(10.0, trainable=True)


@tf.function
def f_x():
    return 2 * x * x - 5 * x + 4


for _ in range(100):
    print([x.numpy(), f_x().numpy()])
    opt = gradient_descent.GradientDescentOptimizer(0.1).minimize(f_x)

最小化Tensorflow中一个变量的功能

2 个答案: