Question

PHP noob在这里。我已经写出了试图从数据库中获取数据的第8步，但我的第一行只是回复了

“注意：未定义的索引：itemid in 第130行的C：\ xampp \ htdocs \ 1605267B \ KUSO \ cart.php“

我在第一行使用GET功能时发现没有任何问题。请帮帮我。

<?php

$itemid = $_GET['itemid'];

//TODO 1: Connect to forumdb database
$mysqli = new mysqli("localhost","root",null,"kuso");

//TODO 2: Prepare the statement to select message id and subject info belonging to $userid from forummessage table 
$stmt = $mysqli->prepare("select itemid, itemname, itempicture, description, price from items where itemid=?");

//TODO 3: Bind the values   
$stmt->bind_param("i",$itemid);

//TODO 4: Execute the statement
$stmt->execute();

//TODO 5: bind results into $messageid, $subject
$stmt->bind_result($itemid, $itemname, $itempicture, $description, $price);

echo "<table border='1'>";
echo "<tr><td><b>Subject</b></td><td><b>Actions</b></td></tr>";

// Use while loop to fetch messages and put in a <table>
while ($stmt->fetch()) {
    echo "<tr>";
    //TODO 6: In 1st <td>, display subject
    echo "Sliim-fit.jpg";
    echo "<a href='menschoice.php?productid==$itemid'>";

    //TODO 7: In 2nd <td>, display View hyperlink with messageid in query string.
    //The View hyperlink links to messagedetails.php
    echo "<td> <a href='messagedetails.php?messageid=$messageid'> View </a></td>";

    echo "</tr>";
}

echo "</table>";


//TODO 8: close the statement
$stmt->close();

//TODO 9: close $mysqli
$mysqli->close();

?>

我不知道为什么它一直让我退回未定义的索引。帮助我感谢senpais。

Answer 1

更改以下行

$itemid = $_GET['itemid'];

使用

$itemid = !empty($_GET['itemid'])  ? $_GET['itemid'] : 0;

如果您不想显示任何匹配项，则零应为任何默认ID或0。

使用GET函数

1 个答案: