Question

我正在尝试打开三个不同的LED，但我希望它们在不同的时间关闭，但这看起来不可能......：哭：这是我的代码：

import RPi.GPIO as GPIO 
import time from threading 
import Thread 
def led1(): 
GPIO.setmode(GPIO.BOARD) 
GPIO.setup(36, GPIO.OUT) 
GPIO.output(36,1) 
time.sleep(3) 
GPIO.output(36,0) 
GPIO.setwarnings(False) 
def led2(): GPIO.setmode(GPIO.BOARD) 
GPIO.setup(38, GPIO.OUT) 
GPIO.output(38,1) 
time.sleep(5) 
GPIO.output(38,0) 
GPIO.setwarnings(False) 
def led3(): 
GPIO.setmode(GPIO.BOARD) 
GPIO.setup(40, GPIO.OUT) 
GPIO.output(40,1) 
time.sleep(7) 
GPIO.output(40,0) 
GPIO.setwarnings(False) 
thread1= Thread(target = led1) 
thread2= Thread(target = led2)
thread3= Thread(target = led3) 
thread1.run() thread2.run() 
thread3.run() 
##thread1.join () // not sure if I have to put that or not 
##thread2.join() 
##thread3.join() 
GPIO.cleanup()

Answer 1

为什么不做这样的事情？

import RPi.GPIO as GPIO
import time

GPIO.setmode(GPIO.BOARD)
GPIO.setup(36, GPIO.OUT)
GPIO.setup(38, GPIO.OUT)
GPIO.setup(40, GPIO.OUT)
GPIO.setwarnings(False)

GPIO.output(36,1)
GPIO.output(38,1)
GPIO.output(40,1)

time.sleep(3)
GPIO.output(36,0)
time.sleep(2)
GPIO.output(38,0)
time.sleep(2)
GPIO.output(40,0)

GPIO.cleanup()

编辑：如果你不知道每个led的开启次数：

import RPi.GPIO as GPIO
import time

GPIO.setmode(GPIO.BOARD)
GPIO.setup(36, GPIO.OUT)
GPIO.setup(38, GPIO.OUT)
GPIO.setup(40, GPIO.OUT)
GPIO.setwarnings(False)

led1time = 3
led2time = 5
led3time = 7
m = max(led1time, led2time, led3time)

GPIO.output(36,1)
GPIO.output(38,1)
GPIO.output(40,1)

t = 0
while t <= m:
    if t >= led1time:
        GPIO.output(36,0)
    if t >= led2time:
        GPIO.output(38,0)
    if t >= led3time:
        GPIO.output(40,0)
    time.sleep(0.1)
    t += 0.1

GPIO.cleanup()

现在，您可以设置每个LED的开启时间，准确度为0.1秒，您可以通过用较低的数字替换任何出现的0.1来提高准确度。

多个LED在不同时间

1 个答案: