我希望再次提示用户是否输入了可接受范围(0-100)之外的双倍,直到输入有效。当输入被认为有效时,我想返回正确的输入值,但是返回的是第一个不正确的值。如何返回正确的输入,如if语句所接受的那样?非常感谢!
public class examscore {
public static void main (String[] args) {
Scanner console = new Scanner(System.in);
double sumfin = finalscore(console);
System.out.println(sumfin); // if user input is initially invalid, but then corrected, the first, incorrect, value is printed
}
public static double finalscore (Scanner console) {
System.out.println();
System.out.println("Input final exam score: ");
while(!console.hasNextDouble()) { //prompts the user, if invalid input, to input again, until a valid value is input
System.out.println("Please input a mark between 0 and 100. ");
console.next();
}
double examscore = console.nextDouble();
if (examscore >=0 && examscore<= 100) {
System.out.println();
System.out.println("Exam Score = "+examscore);
} else {
System.out.println("Error:");
finalscore (console);
}
return examscore; //an attempt to return the VALID exam score: fails
}
}
答案 0 :(得分:1)
do-while循环非常适合。例如:
Scanner console = new Scanner(System.in);
double userInput = 0;
do {
System.out.println("Please input a mark between 0 and 100. ");
try {
userInput = console.nextDouble();
} catch (InputMismatchException e) {
System.out.println("Your input could not be interpreted as a floating-point number.");
}
} while (userInput <= 0D || userInput >= 100D);
答案 1 :(得分:0)
您错过了将finalscore(控制台)的结果分配给else块内的考试核心。
if (examscore >= 0 && examscore <= 100) {
System.out.println();
System.out.println("Exam Score = " + examscore);
} else {
System.out.println("Error:");
examscore = finalscore(console);
}
答案 2 :(得分:0)
您可以使用循环或递归调用来完成此操作。我更喜欢递归调用:
private static double getValidScore(Scanner console) {
System.out.println();
System.out.println("Input final exam score: ");
try {
double score = Double.parseDouble(console.nextLine());
if (score >= 0 && score <= 100) {
return score;
}
} catch (NumberFormatException nfe) {}
System.out.println("Please input a mark between 0 and 100.");
return getValidScore(console);
}