Question

使用pyopengl，我正在尝试创建一个圆柱体。圆柱体的顶部不是圆形的，而底部是如下图所示的图像所示。我想知道如何解决这个问题，如果它是我编码它的方式，或者只是我做的方式不适用于pyopengl。我使用的是Pygame 1.9.2，Python 3.5和PyOpenGL-3.1.0。

https://i.stack.imgur.com/KYPLY.jpg

import pygame
from pygame.locals import *

from OpenGL.GL import *
from OpenGL.GLU import *





def securityCamera(radius,halflength,slices):
    glBegin(GL_TRIANGLES)
    for i in range(1,slices+1):
        angleSize=(2*math.pi)/slices
        theta=i*angleSize
        nextTheta=(i+1)*angleSize

        glColor3fv((0/256,0/256,0/256))

        glVertex3f(radius*math.cos(nextTheta), halflength, radius*math.cos(nextTheta))
        glVertex3f(radius*math.cos(theta), halflength, radius*math.sin(theta))
        glVertex3f(0.0, halflength, 0.0)

        glVertex3f(radius*math.cos(nextTheta), -halflength, radius*math.sin(nextTheta))
        glVertex3f(radius*math.cos(theta), -halflength, radius*math.sin(theta))
        glVertex3f(0.0, -halflength, 0.0)

    glEnd()

    glBegin(GL_QUADS)
    for i in range(1,slices+1):
        angleSize=(2*math.pi)/slices
        theta=i*angleSize
        nextTheta=(i+1)*angleSize


        glColor3fv((256/256,256/256,256/256))
        glVertex3f(radius*math.cos(theta), halflength, radius*math.sin(theta))
        glVertex3f(radius*math.cos(nextTheta), halflength, radius*math.cos(nextTheta))
        glVertex3f(radius*math.cos(theta), -halflength, radius*math.sin(theta))
        glVertex3f(radius*math.cos(nextTheta), -halflength, radius*math.sin(nextTheta))
    glEnd()

Answer 1

圆柱体可分为两个圆形和一个连接两个圆形的矩形管/片。为避免重复某些顶点，我使用GL_TRIANGLE_FAN（对于圆圈）和GL_TRIANGLE_STRIP（对于管道）而不是GL_TRIANGLE和GL_QUAD。如果您想了解更多相关信息，建议您查看this回答。

下面是一个演示，显示一个旋转圆柱，中间有一个红色端，一个蓝色端和一个绿色管（重要代码在draw_cylinder函数中）：

import pygame
from pygame.locals import *
from OpenGL.GL import *
from OpenGL.GLU import *
import math
import sys

def draw_cylinder(radius, height, num_slices):
    r = radius
    h = height
    n = float(num_slices)

    circle_pts = []
    for i in range(int(n) + 1):
        angle = 2 * math.pi * (i/n)
        x = r * math.cos(angle)
        y = r * math.sin(angle)
        pt = (x, y)
        circle_pts.append(pt)

    glBegin(GL_TRIANGLE_FAN)#drawing the back circle
    glColor(1, 0, 0)
    glVertex(0, 0, h/2.0)
    for (x, y) in circle_pts:
        z = h/2.0
        glVertex(x, y, z)
    glEnd()

    glBegin(GL_TRIANGLE_FAN)#drawing the front circle
    glColor(0, 0, 1)
    glVertex(0, 0, h/2.0)
    for (x, y) in circle_pts:
        z = -h/2.0
        glVertex(x, y, z)
    glEnd()

    glBegin(GL_TRIANGLE_STRIP)#draw the tube
    glColor(0, 1, 0)
    for (x, y) in circle_pts:
        z = h/2.0
        glVertex(x, y, z)
        glVertex(x, y, -z)
    glEnd()

pygame.init()
(width, height) = (800, 600)
screen = pygame.display.set_mode((width, height), OPENGL | DOUBLEBUF)
clock = pygame.time.Clock()
rotation = 0.0

while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()

    rotation += 1.0
    glClear(GL_COLOR_BUFFER_BIT)
    glClear(GL_DEPTH_BUFFER_BIT)
    glEnable(GL_DEPTH_TEST)

    glMatrixMode(GL_PROJECTION)
    glLoadIdentity()
    gluPerspective(30, float(width)/height, 1, 1000)
    glMatrixMode(GL_MODELVIEW)
    glLoadIdentity()
    glTranslate(0, 0, -50)#move back far enough to see this object 
    glRotate(rotation, 0, 1, 0)#NOTE: this is applied BEFORE the translation due to OpenGL multiply order

    draw_cylinder(5, 10, 20)
    pygame.display.flip()
    clock.tick(60)

顺便说一句，你可能已经意识到像glBegin和glVertex这样的固定功能方法真的很古老而且已经过时了，但我认为提及它并不会有什么坏处。使用这种代码，您基本上是一次向GPU发送一个顶点，这不是很有效。如果您在未来遇到性能问题，可能需要查看VBO。希望这有帮助！

pyopengl - 在不使用gluCylinder功能的情况下创建圆柱体

1 个答案: