Question

这是我的阵列：

var testeArray = [
    {name: "Jovem1", esteira: "Macaco"},
    {name: "Jovem", esteira: "Doido", horse: "Chimbinha"}
];

从上面，我想得到一个这样的数组：

var propertyName = ["name", "esteira", "horse"];

该数组包含对象数组中对象的所有属性名称。我试过了Form array of property names found in a JavaScript Object但结果是：

['0', '1']

Answer 1

您可以使用Array#forEach迭代数组，并使用Object.keys获取密钥并收集对象中的名称。然后取得钥匙。

＆＃13;

var testeArray = [{name: "Jovem1", esteira: "Macaco"}, {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }],
    names = Object.create(null),
    result;

testeArray.forEach(function (o) {
    Object.keys(o).forEach(function (k) {
        names[k] = true;
    });
});

result = Object.keys(names);
console.log(result);

＆＃13;

ES6与Set和spread syntax ...

＆＃13;

var array = [{name: "Jovem1", esteira: "Macaco"}, {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }],
    names = [...array.reduce((s, o) => (Object.keys(o).forEach(k => s.add(k)), s), new Set)];
console.log(names);

＆＃13;

Answer 2

您可以非常简单地执行以下操作;我认为到目前为止它可能是效率最高的代码。

＆＃13;

var testArray = [
    {name: "Jovem1", esteira: "Macaco"},
    {name: "Jovem", esteira: "Doido", horse: "Chimbinha"}
],
props = Object.keys(testArray.reduce((o,c) => Object.assign(o,c)));
console.log(props);

＆＃13;

Answer 3

var testArray = [{
  name: "Jovem1",
  esteira: "Macaco"
}, {
  name: "Jovem",
  esteira: "Doido",
  horse: "Chimbinha"
}];

var propName = [];

testArray.forEach(function(o) {
  Object.keys(o).forEach(function(prop) {
    if (propName.indexOf(prop) < 0)
      propName.push(prop);
  });
});

console.log(propName);

Answer 4

首先使用Object.keys从数组中获取所有属性，然后过滤掉以获取不同的属性

var testeArray = [
    {name: "Jovem1", esteira: "Macaco"},
    {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }
  ]

var properties = [];
testeArray.forEach(function (o) {
    Object.keys(o).forEach(function (k) {
        properties.push(k)
    });
});

var distProps = properties.filter(function(item, i, arr) {
    return arr.indexOf(item) === i;
})
console.log(distProps);

Answer 5

您可以尝试这样的事情：

 var testeArray = [
    {name: "Jovem1", esteira: "Macaco"},
    {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }
  ];

// The array in which we push the unique property names.
var properties = [];

testeArray.forEach(function(obj){
    for(var key in obj){
       if(obj.hasOwnProperty(key) 
          && properties.indexOf(key) === -1) { 
          // It's the first time we hit key. So push it to the array.
         properties.push(key);
       }
    }
});

console.log(properties);

Answer 6

使用Array.prototyp.reduce()和Object.keys()函数的

Ecmascript5 解决方案：

var testeArray = [
    {name: "Jovem1", esteira: "Macaco"},
    {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }
  ],
    keys = testeArray.reduce(function(r, o) {
        Object.keys(o).forEach(function (k) {
            if (r.indexOf(k) === -1) r.push(k);
        })
        return r;
    }, []);

console.log(keys);

使用Set个对象和Array.from函数的

Ecmascript6 解决方案：

var testeArray = [
    {name: "Jovem1", esteira: "Macaco"},
    {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }
  ],
    keys = testeArray.reduce(function(r, o) {
        var newSet = new Set(Object.keys(o));
        return new Set([...r, ...newSet]);
    }, new Set());

console.log(Array.from(keys));

[...r, ...newSet]中的

new Set([...r, ...newSet])表示r和newSet转换为数组并连接。

Answer 7

＆＃13;

function collectProperties(arrayOfObjects) {
  return arrayOfObjects.reduce(function(memo, object) {
    Object.keys(object).forEach(function(key) {
      if (memo.indexOf(key) === -1) { memo.push(key) };
    });
    return memo;
  }, []);
}

var testArray = [
  {name: "Jovem1", esteira: "Macaco"},
  {name: "Jovem", esteira: "Doido", horse: "Chimbinha"}
];

console.log(collectProperties(testArray));

＆＃13;

因此collectProperties(testeArray)会返回['name', 'esteira', 'horse']。

或者在CoffeeScript中：

collectProperties = (arrayOfObjects) ->
  properties = []
  for object in arrayOfObjects
    for own property of object when property not in properties
      properties.push(property)
  properties

testArray = [
  {name: "Jovem1", esteira: "Macaco"}
  {name: "Jovem", esteira: "Doido", horse: "Chimbinha"}
]

console.log(collectProperties(testArray))

Answer 8

使用ES6，您可以使用Set并传播语法...来执行此操作。

＆＃13;

var testeArray = [
  {name: "Jovem1", esteira: "Macaco"},
  {name: "Jovem", esteira: "Doido", horse: "Chimbinha" }
];

var result = [...new Set([].concat(...testeArray.map(e => Object.keys(e))))]
console.log(result)

＆＃13;

如何获取数组中对象的属性名称？

8 个答案: