Question

假设我有一个SQL查询：

[h(n) for n in range(1,7)]

哪种方法正常：2, 5, 41, 2306, 8143397, 94592167328105语句将SELECT phone_id, name FROM calls c WHERE (c.user_id = 2241 AND c.phone_id IN ("Google Pixel","Samsung") AND (c.name IN ("Alex","John")) OR c.name IS NULL) IS TRUE)表达式计算为单个表达式。

但问题是Doctrine不支持IS TRUE语句，而且此类查询会导致错误。

如何使用Doctrine实现相同的功能，但很明显避免(c.name IN ("Alex","John")) OR c.name IS NULL)陈述？

Answer 1

评论太长了。

is true的目的是什么？

为什么不直接写这个查询呢？

SELECT phone_id, name
FROM calls c
WHERE c.user_id = 2241 AND
      c.phone_id IN ('Google Pixel', 'Samsung') AND
      (c.name IN ('Alex', 'John') OR c.name IS NULL)

在Doctrine中使用IS TRUE sql语句

1 个答案: